Answer:
1. C+ ---- O-
2. O+ ---- Cl-
3. O+ ----- F-
4. C+ ----- N-
5. Cl- ----- C+
6. S- ----- H+
7. S+ ----- Cl -
Explanation:
Electronegativity determines the polarity . There may be two atoms in a bond with high electronegativity, in such cases the positive charge is given to atom with comparatively lower electronegativity. Electronegativity determines the easiness with which an atom attract electrons in a chemical bond. A polar bond is formed when the difference in the electronegativity of two combining atoms is between 0.4 and 1.7. The correct direction is
1. C+ ---- O-
2. O+ ---- Cl-
3. O+ ----- F-
4. C+ ----- N-
5. Cl- ----- C+
6. S- ----- H+
7. S+ ----- Cl -
Answer :
Lewis-dot structure : It shows the bonding between the atoms of a molecule and the unpaired electrons present in the molecule.
The given molecule is, 
Beryllium has '2' valence electrons and fluorine has '7' valence electrons. Beryllium is the central atom and fluorine is the terminal atom.
Total number valence electrons in = 2 + 2(7) = 16
According to the Lewis-dot structure, there are '4' number of bonding electrons and 12 number of non-bonding electrons (lone-pair).
The Lewis-dot structure is shown below.
Answer: This is an oxidation-reduction (redox) reaction:
3 C-II - 12 e- → 3 CII (oxidation)
4 CrVI + 12 e- → 4 CrIII (reduction)
C2H5OH is a reducing agent, K2Cr2O7 is an oxidizing agent.
Answer: Atom/element
Explanation: Since matter cannot be created or destroyed, the number of atoms has to be equal on both sides of the equation.
₁₅P 1s²2s²2p⁶3s²3p³
₁₆S 1s²2s²2p⁶3s²3p⁴
It is because: 1) phosphorus have 3 unpaired electrons in 3p shell, and that is more stable than 3p⁴ in sulfur, so it ie easier to remove 1 paired electron in sulphur to became 3p³.
2) repulsion in 3p shell in sulfur between 2 paired electrons is higher, so it is easier to remove that electron.
