1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
almond37 [142]
2 years ago
15

Init.

Physics
2 answers:
nikklg [1K]2 years ago
8 0

Answer:

The kilogram, symbol kg, is the SI unit of mass. It is defined by taking the fixed numerical value of the Planck constant h to be 6.62607015×10−34 when expressed in the unit J⋅s, which is equal to kg⋅m2⋅s−1, where the metre and the second are defined in terms of c and ΔνCs.

sammy [17]2 years ago
5 0

Answer:

The kilogram (abbreviation, kg) is the standard international (SI)system of units.it was originally defined as the mass of 1 litre(10-3 cubic meter) of pure water.At the earth's surface ,a mass of 1 kg weight approximately 2.20 pounds (IB)

Explanation:

the force of attraction exerted by the earth on a body of certain mass. It's SI unit is Newton(N).

You might be interested in
A person exerts a tangential force of 37.7 N on the rim of a disk-shaped merry-go-round of radius 2.75 m and mass 144 kg. If the
Shkiper50 [21]

Answer:

 ω = 0.467 rad/s

Explanation:

given,

tangential force exerted by the person = 37.7 N

radius of merry-go-round = 2.75 m

mass of merry-go-round  = 144 Kg

angle =  33.2°

moment of inertia

I = \dfrac{1}{2} m R^2

I = \dfrac{1}{2}\times 144 \times 2.75^2

    I = 544.5 kg.m²

torque = force  x radius

τ = 37.7 x  2.75

τ = 103.675 N.m

angular acceleration

\alpha= \dfrac{\tau}{I}

\alpha= \dfrac{103.675}{544.5}

 α = 0.190 rad/s²

now ,

distance = 33.2\times \dfrca{2\pi}{360}

d = 0.579 rad

we know,

using equation of rotational motion

d = \omega t + \dfrac{1}{2}\alpha t^2

0.579 = \dfrac{1}{2}\times 0.190\times t^2

 t = 2.46 s

angular speed

 ω =  α  x t

 ω = 0.19 x 2.46

 ω = 0.467 rad/s

7 0
2 years ago
You treat 9.540 g of the mixture with the acid and isolate 9.355 g of nacl. what is the weight percent of each substance in the
Mila [183]

The weight percentage of sodium carbonate in the mixture is = 67.71%  

The weight percentage of sodium bicarbonate in the mixture is = 32.57%

<h3>What does "molar mass" ?</h3>

The total mass throughout grams of all the atoms needed to form a molecule per mole is what makes up the molar mass, also known as the molecular weight. Grams per mole is the unit measuring molar mass.

<h3>According to the given information:</h3>

The interaction between sodium carbonate and hydrochloric acid has the following equation:

Na₂CO₃ + HCl  --> NaCl  + CO₂ + H₂O

The reaction's balanced equation is,

Na₂CO₃ + 2HCl  --> 2NaCl  + CO₂ + H₂O -------(2).

When sodium hydrogen carbonate as well as hydrochloric acid react, the following equation results.

NaCO₃ + HCl  --> NaCl  + CO₂ + H₂O ----------------(3)

The Molar mass :

Na₂CO₃ = 106g/mol

NaCO₃ = 84g/mol

NaCl  = 58.5g/mol

The mass of the mixture is Na₂CO₃/NaCO₃ = 9.540g

The molar masses of the constituent elements that make up the compounds are added to determine the molar weight of the substances. In both chemical equations (2) and (3), the unitary technique is employed to calculate the mass of the mixture based on the number of moles (3).

The mass of the sodium carbonate and sodium bicarbonate is calculated with the help of the mass of NaCl formed by the mixture of  Na₂CO₃/NaCO₃ with HCl.

The mixture has the following percentage of sodium carbonate:

        % of Na₂CO₃ =  \frac{x \times 106}{9.540} \times 100\\

                             =\frac{0.061 \times 106}{9.540} \times 100

                             = (6.46/9.540)*100

                             = 67.71%        

The weight percentage of sodium carbonate in the mixture is = 67.71%      

The mixture has the following percentage of NaHCO3:

        % of NaHCO₃ =  \frac{y \times 84}{9.540} \times 100

                             = =\frac{0.037 \times 84}{9.540} \times 100

                              = (3.108/9.540)*100

                             = 32.57%

The weight percentage of sodium bicarbonate in the mixture is = 32.57%

To know more about molar mass visit:

brainly.com/question/12127540

#SPJ4

I understand that the question you are looking for is:

A mixture of sodium carbonate and sodium hydrogen carbonate is treated with aqueous hydrochloric acid. the unbalanced equations for the resulting's reactions are:

Na2CO3 (s) + HCl (aq) --> NaCl (aq) + CO2(g) + H2O (l)

NaHCO3(s) + HCl (aq) --> NaCl (aq) + CO2(g) + H2O (l)

You treat 9.540g of Na2CO3/NaHCO3 mixture with an excess of aqueous HCl and isolate 9.355g of NaCl. What is the weight percent of each substance in the mixture?

5 0
1 year ago
A particle moving on a plane curve what is the degree of freedom
kirill115 [55]

A particle confined to move along a curved path has only one degree of freedom. inclined plane are some examples of constrained motion. Every condition of constraint reduces the number of degree of freedom by one.

I hope this helps!

7 0
2 years ago
A rectangular sharp-crested weir is contracted on both sides, and the opening is 1.2 m wide. At what height (Hw) should it be pl
Alex

Answer:

H_w = 2.129 m

Explanation:

given,

Width of the weir, B = 1.2 m

Depth of the upstream weir, y = 2.5 m

Discharge, Q = 0.5 m³/s

Weir coefficient, C_w = 1.84 m

Now, calculating the water head over the weir

Q = C_w BH^{3/2}

H = (\dfrac{Q}{C_wB})^{2/3}

H = (\dfrac{0.5}{1.84\times 1.2})^{2/3}

H = 0.371\ m

now, level of weir on the channel

H_w = y - H

H_w = 2.5 - 0.371

H_w = 2.129 m

Height at which weir should place is equal to 2.129 m.

7 0
3 years ago
A cube of water 10 cm on a side is placed in a microwave beam having Ea = 11 kV/m‘ The microwaves illuminate one faceofthe cube,
Shtirlitz [24]

Answer:

The time is 133.5 sec.

Explanation:

Given that,

One side of cube = 10 cm

Intensity of electric field = 11 kV/m

Suppose How long will it take to raise the water temperature by 41°C Assume that the water has no heat loss during this time.

We need to calculate the rate of energy transfer from the beam to the cube

Using formula of rate of energy

P=(0.80)IA

P=0.80\times\dfrac{c\mu_{0}E^2}{2}\times A

Put the value into the formula

P=0.80\times\dfrac{3\times10^{8}\times8.85\times10^{-12}\times(1.1\times10^{4})^2}{2}\times(10\times10^{-2})^2

P=1285.02\ W

We need to calculate the amount of heat

Using formula of heat

E =mc\Delta T

E =\rho Vc\Delta T

Put the value into the formula

E=1000\times(0.10)^3\times4186\times41

E=171626\ J

We need to calculate the time

Using formula of time

t=\dfrac{E}{P}

Put the value into the formula

t=\dfrac{171626}{1285.02}

t=133.5\ sec

Hence, The time is 133.5 sec.

3 0
3 years ago
Other questions:
  • Suppose that the electric potential outside a living cell is higher than that inside the cell by 0.063 V. How much work is done
    13·1 answer
  • An 73 cm long pendulum with a 0.80 kg bob is released from rest at an initial angle of θ0 with the vertical. at the bottom of th
    13·1 answer
  • A Ray of light in air makes an angle of 45 degree at the surface of a sheet of ice . the ray is refracted within the Ice at an a
    9·1 answer
  • a car traveling at 40m/s starts to decelerate steadily. it comes to a complete stop in 12 seconds. what is the acceleration?
    11·1 answer
  • What is meant by the "lever arm" of a torque?
    8·1 answer
  • A 2000 N net force will give a car with some amount of mass an acceleration of 4 m/s2
    15·1 answer
  • What would be the difference between kinetic and potential energy​
    6·1 answer
  • Find the force of gravity between a cubic meter of water (1000kg) and the Sun. The Sun's mass is 1.99 x10^30 kg and is 1.50 x10^
    15·1 answer
  • Please HELPPPPP!
    7·1 answer
  • A jet airplane is in level flight. The mass of the airplane is m=8950 kg. The airplane travels at a constant speed around a circ
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!