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3 years ago

A yo-yo is twirled on a 4 meter long string so that its tangential

Physics

1 answer:

Veseljchak [2.6K]3 years ago

7 0

Answer:

8m/s

Explanation:

i think i had this question on a test i'm taking so i'm assuming i cannot say for sure if this is correct

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Instructions:Select the correct answer. Research shows that Mount Everest grows an average of 4 millimeters each year. How many

Artemon [7]

Very easy....4 millimeters is the growth every year..as 720 mm is the final one...we can divide it by 4mm to obtain the answer..I.E=180years

8 0

4 years ago

Read 2 more answers

A 4.0 kg object will have a weight of approximately 14.8 N on Mars. What is the gravitational field strength on M

Pie

Answer:

Gravitational field strength =weight/mass

Explanation:

14.8N/4.0kg

3.7N/kg

3 0

3 years ago

What does it mean to say that the average speed of a car is 35 miles per hour?

LenKa [72]

It means that the car has covered

(35 miles) x (the number of hours since it started traveling).

At some points during that time, the car was most likely moving
faster or slower than 35 miles per hour. We don't know. We only
know that it covered (35 miles) x (the number of hours since it left).

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3 years ago

Points P and Q are located at (0, 2, 4) and (-3, 1,5). Calculate

Akimi4 [234]

Answer:

a) The position vector of P is $\vec P =(0, 2,4)$ .

b) The distance vector from P to Q is $\overrightarrow{PQ} = (-3,-1,1)$ .

c) The distance between P and Q is $\|\overrightarrow{PQ}\|=\sqrt{11}$ .

d) A vector parallel to PQ with magnitude of 10 is $\vec v = \left(-\frac{30\sqrt{11}}{11},-\frac{10\sqrt{11}}{11}, \frac{10\sqrt{11}}{11} \right)$ .

Explanation:

a) The position vector of a point is the vector displacement from the origin to the location of the point. That is:

$\vec P = (0,2,4)-(0,0,0)$

$\vec P = (0-0, 2-0, 4-0)$

$\vec P =(0, 2,4)$

The position vector of P is $\vec P =(0, 2,4)$ .

b) First, we calculate the position vector of point Q:

$\vec Q = (-3,1,5)-(0,0,0)$

$\vec Q = (-3-0,1-0,5-0)$

$\vec Q =(-3,1,5)$

The distance vector from P to Q is define by the following vectorial expression:

$\overrightarrow{PQ} = \vec Q - \vec P$ (1)

$\overrightarrow{PQ} = (-3,1,5)-(0,2,4)$

$\overrightarrow{PQ} =(-3-0,1-2,5-4)$

$\overrightarrow{PQ} = (-3,-1,1)$

The distance vector from P to Q is $\overrightarrow{PQ} = (-3,-1,1)$ .

c) There are two approaches to calculate the distance between P and Q:

First Method - Pythagorean Theorem:

$\|\overrightarrow{PQ}\| = \sqrt{(-3)^{2}+(-1)^{2}+1^{2}}$

$\|\overrightarrow{PQ}\|=\sqrt{11}$

Second Method - Dot Product:

$\|\overrightarrow{PQ}\| = \sqrt{\overrightarrow{PQ}\,\bullet\,\overrightarrow{PQ}}$ (2)

$\|\overrightarrow{PQ}\| = \sqrt{(-3,-1,1)\,\bullet (-3,-1,1)}$

$\|\overrightarrow{PQ}\|=\sqrt{11}$

The distance between P and Q is $\|\overrightarrow{PQ}\|=\sqrt{11}$ .

d) To determine a vector parallel to PQ with a given magnitude is determined by the following expression:

$\vec v = \frac{k}{\|\overrightarrow{PQ}\|} \cdot \overrightarrow{PQ}$ (3)

Where $k$ is the scale factor.

If we know that $\overrightarrow{PQ} = (-3,-1,1)$ , $\|\overrightarrow{PQ}\|=\sqrt{11}$ and $k = 10$ , then the vector is:

$\vec v = \frac{10}{\sqrt{11}}\cdot (-3,-1,1)$

$\vec v = \left(-\frac{30}{\sqrt{11}},-\frac{10}{\sqrt{11}},\frac{10}{\sqrt{11}}\right)$

$\vec v = \left(-\frac{30\sqrt{11}}{11},-\frac{10\sqrt{11}}{11}, \frac{10\sqrt{11}}{11} \right)$

A vector parallel to PQ with magnitude of 10 is $\vec v = \left(-\frac{30\sqrt{11}}{11},-\frac{10\sqrt{11}}{11}, \frac{10\sqrt{11}}{11} \right)$ .

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3 years ago

If cake baking is compared to protein synthesis, what genetic structure would be analogous to the flour, sugar, and eggs?

galina1969 [7]

Mrnmrnamrnamrnamrnamrnamrnamrnamrnamrnamrna

7 0

3 years ago