Answer:


And then the percentage between 24 and 40 would be 
Step-by-step explanation:
For this problem we have the following parameters given:

And for this case we want to find the percentage of lightbulb replacement requests numbering between 24 and 40.
From the empirical rule we know that we have 68% of the values within one deviation from the mean, 95% of the values within 2 deviations and 99.7% within 3 deviations.
We can find the number of deviations from themean for the limits with the z score formula we got:

And replacing we got:


And then the percentage between 24 and 40 would be 
Answer: y=3/4x+3
Step-by-step explanation:
Here, p^ = (0.39 + 0.47)/2 = 0.43
The given interval is (0.43 - 0.04, 0.43 + 0.04).
Therefore, the margin of error is 0.04.
Let's calculate the total cost per year:
6168 + 3280 + 2190 + 1200 = 12,838.
Four years will cost 12838 x 4 = 51,352
Your family will help you out with 17,600, so you will need to pay:
51352 - 17600 = 33,752
First do the equations in the parentheses
(21)+(28) the first one isn't negative anymore because a negative times a negative is a positive.
Now we just add them, 21+28=49