The correct answer is decreases
The further away you are the weaker it would be. That's why at one point you stop being in the field and ti doesn't pull you towards it anymore. Proportionally, if you move towards the Earth then it increases.
Answer:
I may be wrong sir/ma’am, but I believe it’s 1. Surface temperatures. 3.radio signals from space. And 4. Distance of stars.
Explanation:
sorry y’all:(
Answer:
0.78 m
Explanation:
By the conservation of energy, the energy that they gain from potential energy, must be equal to the kinetic energy. So, for Adolf:
Ep = Ek
ma*g*ha = ma*va²/2
Where ma is the mass of Adolf, g is the gravity acceleration (10 m/s²), ha is the height that he reached, and va is the velocity. So:
100*10*0.51 = 100*va²/2
50va² = 510
va² = 10.2
va = √10.2
va = 3.20 m/s
Before the push, both of them are in rest, so the momentum must be 0. The system is conservative, so the momentum after the push must be equal to the momentum before the push:
ma*va + me*ve = 0, where me and ve are the mass and velocity of Ed. So:
100*3.20 + 81ve = 0
81ve = 320
ve = 3.95 m/s
By the conservation of energy for Ed:
me*g*he = me*ve²/2
81*10*he = 81*(3.95)²/2
810he = 631.90
he = 0.78 m
Answer:
Current, I = 3.57A
Explanation:
A current of I amperes means that I Coulombs of charge flows through the conductor (heating coil) per second.
Therefore, in time t, the total charge (Q) passing through any point in which the current (C) flows will be given by the equation;
Q = It
Where; Q is the charge in coulombs; I is the current in amperes; t is the time in seconds.
From the question, we were given the following parameters;
Q = 25C, t= 7secs and I =?
From the equation, Q = It
We make current, I the subject of formula;
Thus, I = Q/t
Substituting into the equation;
I = 25/7
I = 3.57Amp.
