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nikdorinn [45]
3 years ago
8

Velocity is often described as speed with a __________.

Physics
1 answer:
lubasha [3.4K]3 years ago
5 0

Answer:

rate

Explanation:

Note that speed has no direction (it is a scalar) and the velocity at any instant is simply the speed value with a direction.

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Si el periodo de oscilación de resorte es de 0,44 segundos cuando oscila atado a una masa de 2 Kg. ¿Cuál será el valor de la con
boyakko [2]

Answer:

i d k h b u lol I wish I knew it sorry

7 0
2 years ago
On a straight road, a car speeds up at a constant rate from rest to 20 m/s over a 5 second interval and a truck slows at a const
IceJOKER [234]

Answer:

a)

Explanation:

  • Since the car speeds up at a constant rate, we can use the kinematic equation for distance (assuming that the initial position is x=0, and choosing t₀ =0), as follows:

        x_{fc} = v_{o}*t + \frac{1}{2}*a*t^{2}   (1)

  • Since the car starts from rest, v₀ =0.
  • We know the value of t = 5 sec., but we need to find the value of a.
  • Applying the definition of acceleration, as the rate of change of velocity with respect to time, and remembering that v₀ = 0 and t₀ =0, we can solve for a, as follows:

       a_{c} =\frac{v_{fc}}{t} = \frac{20m/s}{5s} = 4 m/s2  (2)

  • Replacing a and t in (1):

       x_{fc} = v_{o}*t + \frac{1}{2}*a*t^{2}  = \frac{1}{2}*a*t^{2} = \frac{1}{2}* 4 m/s2*(5s)^{2} = 50.0 m.  (3)

  • Now, if the truck slows down at a constant rate also, we can use (1) again, noting that v₀ is not equal to zero anymore.
  • Since we have the values of vf (it's zero because the truck stops), v₀, and t, we can find the new value of a, as follows:

       a_{t} =\frac{-v_{to}}{t} = \frac{-20m/s}{10s} = -2 m/s2  (4)

  • Replacing v₀, at and t in (1), we have:

       x_{ft} = 20m/s*10.0s + \frac{1}{2}*(-2 m/s2)*(10.0s)^{2} = 200m -100m = 100.0m   (5)

  • Therefore, as the truck travels twice as far as the car, the right answer is a).
7 0
3 years ago
PLEASE HELP ME
hammer [34]

Answer:

Element Is The Answer I think

6 0
3 years ago
Read 2 more answers
A block slides down a slope inclined at 37 degrees. If the slope is frictionless and the block starts off at rest, how fast is i
lianna [129]

Answer:

Vf= 3.435 m/s

Explanation:

Given:

Initial velocity Vi =0 m/s (starting from Rest position)

θ = 37⁰

Distance S = 1 m

To find: Final Velocity Vf=?

fist we have to find the down slope net acceleration a = g sin θ

a= 9.81 sin  37⁰ = 5.9 m/s²

By 3rd equation of motion

2 a S= Vf² - Vi²

Vf = Square root ( 2 × 5.9 m/s²  × 1  + 0 m/s)

Vf = Square root (11.8)

Vf= 3.435 m/s

3 0
3 years ago
What would happen to the moon if earth stopped exerting the force of gravity on it?
Mila [183]
There are two equal forces of gravity between the Earth and the Moon.
One force pulls the Moon toward the Earth.
The other force pulls the Earth toward the Moon.

If only this gravity suddenly switched off, then the moon would
continue to orbit the Sun, very much as it does now.

If ALL gravity suddenly switched off, then . . .

-- the Moon would stop orbiting the Earth and would sail away, in
a straight line and at the speed it had when gravity disappeared;

-- the Earth would stop orbiting the Sun and would sail away, in
a straight line and at the speed it had when gravity disappeared;

-- all the gases surrounding the Earth ... which we call "air" ... would
start drifting away, and expanding into a giant cloud of gas, and stop
being an atmosphere;

-- the Sun would completely fall apart, expand into a giant cloud of gas,
and stop being a star.
6 0
3 years ago
Read 2 more answers
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