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nikdorinn [45]
3 years ago
8

Velocity is often described as speed with a __________.

Physics
1 answer:
lubasha [3.4K]3 years ago
5 0

Answer:

rate

Explanation:

Note that speed has no direction (it is a scalar) and the velocity at any instant is simply the speed value with a direction.

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A car starts from rest and accelerates to 14 m/s in 2 seconds. What was its acceleration
Romashka [77]

Answer:

7m/s^2

Explanation:

using v=u+at

since the car started from rest, u=0 , v=14m/s t=2s

a =acceleration.

14=0+a×2

14=0+2a

14=2a

a= 14/2 =7

a=7m/s^2

7 0
2 years ago
Ask Questions Action and reaction force pairs are all around you, but they aren't always obvious. Write down
NARA [144]

Answer:

Writing with a pencil. The pencil pushes on the paper. The paper pushes on the pencil.

Explanation:

Newton's third law.

5 0
3 years ago
A block of metal is 3 cm on each side. It has a mass of 283.5 grams. What is the density of the metal.
Luden [163]
Density =  \frac{Mass}{Volume}
\\\rho=\frac{m}{V}
\\\\\rho=\frac{283.5}{3^3}
\\\\\rho=\frac{283.5}{27}
\\\\\rho = 10.5  g/cm^3

5 0
3 years ago
A student thinks that any real vibration must be damped. Is the student correct? If so, give convincing reasoning. If not, give
Stels [109]

Answer:

Yes the student is correct

Explanation:

The first law of thermodynamics states that energy can neither be created nor destroyed

The second law of thermodynamics states that the entropy (disorderliness) of an isolated system always increases

Therefore, whereby energy is not supplied to maintain the orderly oscillatory motion with constant amplitude, the amplitude of the system is bound to reduce with time that is the vibration of the system must be damped

6 0
3 years ago
Two boys with masses of 40 kg and 60 kg stand on a horizontal frictionless surface holding the ends of a light 10-m long rod. Th
zlopas [31]

When they meet the 40-kg boy would have moved a distance of 6 m.

<h3>Distance moved by the 40 kg boy</h3>

Apply the principle of center mass;

Take the 40 kg mass as the reference point;

X(40 kg) = (40kg x 0  + 60kg x 10 m)/(40 kg + 60 kg)

X(40 kg) = (600)/(100)

X(40 kg) = 6 m

Thus, when they meet the 40-kg boy would have moved a distance of 6 m.

Learn more about distance here: brainly.com/question/2854969

#SPJ1

4 0
2 years ago
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