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Amiraneli [1.4K]
3 years ago
9

A car moved 35 km to the South and Then 10 km to the North. What is its Displacement?

Physics
1 answer:
Harrizon [31]3 years ago
3 0

Answer:

It's displacement would be 25 km.

Explanation:

That is because you would subtract 10 from 35 to get the distance away from the starting point.

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Pls hurry!! which organisms have no consumers to feed on them?
umka2103 [35]

Explanation:

All living organisms metabolize. That is the definition of life. So jr answer is no animal or organism that does not consume food.

6 0
3 years ago
A researcher wants to know the effect of lighting on snacking behavior. He knows that young adults normally eat an average of =
horrorfan [7]

Answer:

It does not impact snacking behavior.

Explanation:

The mean of the study was 18.7 grams, which is only 2.3 grams below the actual average grams of snacks that an adult would consume while at work, after revising this you could say that theres a significant reduction, but then the standard deviation is 9.1 this means that there are still adults that are eating more than 21 gram of snacks, so the test would result inconclusive.

8 0
3 years ago
Theory that earth processes occurring today are similar to those that occurred in the past whats the word
Studentka2010 [4]
Its uniformitarianism.
4 0
3 years ago
if you throw a rock straight up at a speed of 19m/s. How long goes it take the ball to reach its maximum height?
Scrat [10]

Answer:

It requires <u>1.9 seconds</u> to reach maximum height.

Explanation:

As per given question,  

Initial velocity (U) =19 m/s

Final velocity (V) = 0 m/s

\text { Taking acceleration due to gravity }(a)=10 \mathrm{m} / \mathrm{s}^{2}

Maximum height = S

Time taken is "t"

<u>Calculating time taken to reach maximum height:</u>

We know that time taken to reach the maximum height is calculated by using the formula V = U + at

Substitute the given values in the above equation.

Final velocity is “0” as there is no velocity at the maximum height.

0=19+10 \times t

-19=10 \times t

\frac{-19}{10}=t

t = 1.9 seconds.

The time taken to reach maximum height is <u>1.9</u> seconds.

<u>Calculating maximum height</u>:

\text { Consider the equation } V^{2}-U^{2}=2 a S

Solving the equation we will get the value of S

0-19^{2}=2 \times(-10) \times \mathrm{S} .(-\text { is due to opposite of gravity) }

-361 = -20S

Negative sign cancel both the sides.

\mathrm{S}=\frac{361}{20}

S = 18.05 m

Maximum height is 18.05 m  .

3 0
3 years ago
Where is the electric field zero? a. region 2, 0.46 m from the +7 µC charge b. region 2, 0.46 m from the +5 µC charge c. the fie
Ratling [72]

Answer:

the field is not zero anywhere on the x axis (except at infinity)

Explanation:

From the Coulomb's law we have electric field intensity as:

E=\frac{1}{4\pi.\epsilon_o} \frac{q}{r^2}

where:

\epsilon_o= permittivity of free space

q= charge due to which the field is generated.

r= distance from the charge

So, from the above relation:

Electric field due to a charge can only be zero at infinity.

3 0
3 years ago
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