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Mrac [35]
3 years ago
15

Jimmy’s family moved to a tropical climate. For the year that followed, he recorded the number of days that had a temperature ab

ove 40 degrees C each month. His data contained -
14, 14, 10, 12, 11, 13, 11, 11, 14, 10, 13 and 8

1) Find the mean for his data set of days that had a temperature above 40 degrees C.

2) Find the median for his data set of days that had a temperature above 40 degrees C.

3) Find the mode for his data set of days that had a temperature above 40 degrees C.

4) If, instead, there are 5 more days per month that had a temperature above 40 degrees C, what will be the mean for the data?

5) If, instead, there are 2 more days per month that had a temperature above 40 degrees C, what will be the mode for the data?

6) If the number of days per month that had a temperature above 40 degrees C, doubles each month in that year, what will be the median for the data?

7) For what value of x will 9, 16, and x have the same mean (average) as that of 26 and 12?

8) For what value of x will 55 and x have the mean (average) as 67?

9) The mean (average) weight of three boys is 40 pounds. One of the boys weighs 50 pounds. The other two boys have the same weight. Find the weight of each of the boys?

10) A cat consumes 2 cups of milk every day. How much milk does that cat drink on an average in a week?

11) What is the mode for the above question?
Mathematics
1 answer:
Phantasy [73]3 years ago
5 0
The answer is 4) as it is more than 40 degrees
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Homework due at 12:00<br> I Need Help
Leya [2.2K]

Answer:

<em>k = - 7.5 </em>

Step-by-step explanation:

Slope "m" of a line through points

( x_{1} , y_{1} )

( x_{2} , y_{2} )

is m = \frac{y_{2} -y_{1} }{x_{2} -x_{1} }

Slopes of perpendicular lines are opposite reciprocal: m_{1} m_{2} = - 1

~~~~~~~~~~~~~~~

The slope of a line through points (0, 7) and (2, 10)

m_{1} = \frac{10-7}{2-0} = \frac{3}{2}

Slope of perpendicular line through points (3, 5) and (k, 12) is m_{2} = -\frac{2}{3}

or m_{2} = \frac{12-5}{k-3}

\frac{7}{k-3} = -\frac{2}{3}

2(k - 3) = - 21

k - 3 = - 10.5

<em>k = - 7.5</em>

6 0
3 years ago
The average weight of a mango, kiwi, peach and banana is 135 grams. The average weight of the mango, kiwi and peach is 120 grams
Kruka [31]

Answer:

200

Step-by-step explanation:

bruh truss me❤️

5 0
3 years ago
How do I find out a mortgage payment on a home
kozerog [31]

Answer:

Step-by-step explanation:by finding how much it costs

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3 years ago
Help please solve<br> <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1
Shkiper50 [21]

Answer:

\displaystyle  -\frac{1}{2} \leq x < 1

Step-by-step explanation:

<u>Inequalities</u>

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0

Simplifying by x-1 and taking x=1 out of the possible solutions:

\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

(6x^3+14x^2+10x+12)

is always positive and doesn't affect the result. It can be neglected. The expression

(x-\frac{1}{2})^2

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0

For the expression to be negative, both signs must be opposite, that is

(x+\frac{1}{2})\geq 0, (x-1)

Or

(x+\frac{1}{2})\leq 0, (x-1)>0

Note we have excluded x=1 from the solution.

The first inequality gives us the solution

\displaystyle  -\frac{1}{2} \leq x < 1

The second inequality gives no solution because it's impossible to comply with both conditions.

Thus, the solution for the given inequality is

\boxed{\displaystyle  -\frac{1}{2} \leq x < 1 }

7 0
3 years ago
Use transformations to solve the equation. c – 16 = 41 A. c = –57 B. c = –25 C. c = 25 D. c = 57
baherus [9]
You should just transfer -16 to the other side so you gonna have : c = 41 + 16 so c = 57 :))
i hope this be helpful
have nice day 
4 0
3 years ago
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