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Law Incorporation [45]
3 years ago
13

How does a sound wave's amplitude affect the sound we hear? How does a sound

Physics
2 answers:
damaskus [11]3 years ago
7 0

Answer:

cause we hear differently

Explanation:

murzikaleks [220]3 years ago
5 0

Answer:

As the amplitude of the sound wave increases, the intensity of the sound increases. Sounds with higher intensities are perceived to be louder. Relative sound intensities are often given in units named decibels (dB)

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N 1800kg car has an<br> of 3.8m/s? What is it<br> on the car?<br> acceleration<br> force acting
nevsk [136]

Answer:

6840 N

Explanation:

The force acting on the car can be found by using Newton's second law:

F = ma

where

F is the net force on the car

m is the mass of the car

a is its acceleration

For the car in this problem,

m = 1800 kg

a=3.8 m/s^2

Substituting,

F=(1800)(3.8)=6840 N

7 0
3 years ago
20.What factor is more important in determining electrical force
Agata [3.3K]

Answer:

20.The first factor is the amount of charge on each object. The greater the charge, the greater the electric force. The second factor is the distance between the charges. The closer together the charges are, the greater the electric force is

Explanation:

6 0
3 years ago
A tool industry characterized by the appearance of hand axes, a bifacial type of blade.
marshall27 [118]
The stone tool industry being described is the Acheulean. These tools are characterized by hand axes and bifacial blades and were made by many different species of Homos, including Homo erectus and early Homo sapiens.
7 0
3 years ago
9) What will happen to the period of a pendulum if we change the rope of a pendulum with another which is four times with the in
Arturiano [62]

Double

Explanation:

Since the period T of a pendulum is given by

T = 2\pi \sqrt{\dfrac{l}{g}}

By increasing the length of the pendulum by 4, the period becomes

T' = 2\pi \sqrt{\dfrac{4l}{g}} = 2\left(2\pi \sqrt{\dfrac{l}{g}}\right) = 2T

You can see that the period doubles when we increase the length by a factor of 4.

5 0
3 years ago
A space probe is launched from Earth headed for deep space. At a distance of 10,000 miles from Earth's center, the gravitational
Pavlova-9 [17]
<span> gravitational force varies based on 1/r^2
when you're double the distance =10,000 to 20,000, the force is 4 times smaller so on and so forth.
</span><span>As force is proportional to 1 / {distance squared}, the force will be 1 / 2^2 (i.e. 1/4) of the force at the reference distance (i.e. 1/4 * 600 = 150 lb)
</span>hope this helps
5 0
3 years ago
Read 2 more answers
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