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KATRIN_1 [288]
3 years ago
11

PLEASE HELP ASAP IM BEING TIMED! WILL GIVE YOU 50 POINTS!! What were the long term impacts of the development of Boyle's Law? Th

e discovery of oxygen? The law of conservation?
Chemistry
1 answer:
pav-90 [236]3 years ago
8 0

The answer to the question is the discovery of oxygen

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Deduce the formula of the ion that has a charge of 2+ with the same electron configuration as krypton.
Andrews [41]

Answer:

Sr²⁺

Explanation:

Krypton has 36 electrons and an electron configuration of 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6. An ion with a charge of 2+ and 36 electrons is Sr²⁺. Since it has the same amount of electrons, Sr²⁺ also has an electron configuration of 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6.

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Help please-
anzhelika [568]

Answer:

Oxygen and Carbon are in the non-metal section. Both are in 2nd period while Carbon is in group 4A and Oxygen is in group 6A.

Oxygen has more valence electrons than carbon. I wish I could give you a more accurate explanation why on paper, but all you need to do is count the electrons on the largest shell.

Here's the orbital notation of Carbon: 1s^2 2s^2 2px^1 py^1

Carbon's largest shell is 2. Count the electrons on shell 2, and you get 4 valence electrons.

Orbital notation of Oxygen: 1s^2 2s^2 2px^2 py^1 pz^1

Oxygen's largest shell is 2. So, like with carbon, count the electrons on the largest shell. You get 6.

There is a way easier way of interpreting this where you do not even have to write the orbital notation. I wish I can explain, but just know the periods and the group numbers.

7 0
3 years ago
Convert 150 kPa to atmospheres. *
lakkis [162]

Answer: 1.48 atmosphere

Explanation:

Pressure in kilopascal = 150

Pressure in atmosphere = ?

Recall that 1 atmosphere = 101.325 kilopascal

Hence, 1 atm = 101.325 kPa

Z atm = 150 kPa

To get the value of Z, cross multiply

150 kPa x 1 atm = 101.325 kPa x Z

150 kPa•atm = 101.325 kPa•Z

Divide both sides by 101.325 kPa

150 kPa•atm/101.325 kPa = 101.325 kPa•Z/101.325 kPa

1.48 atm = Z

Thus, 150 kPa is equivalent to 1.48 atmospheres

7 0
3 years ago
The hypothetical elements shown here (figures a–d) do not include hydrogen or helium. Which element would you expect to bond cov
Marizza181 [45]
The answer is "Figure a" i did it on plato lol
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3 years ago
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