1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nasty-shy [4]
3 years ago
14

Convert 150 kPa to atmospheres. *

Chemistry
1 answer:
lakkis [162]3 years ago
7 0

Answer: 1.48 atmosphere

Explanation:

Pressure in kilopascal = 150

Pressure in atmosphere = ?

Recall that 1 atmosphere = 101.325 kilopascal

Hence, 1 atm = 101.325 kPa

Z atm = 150 kPa

To get the value of Z, cross multiply

150 kPa x 1 atm = 101.325 kPa x Z

150 kPa•atm = 101.325 kPa•Z

Divide both sides by 101.325 kPa

150 kPa•atm/101.325 kPa = 101.325 kPa•Z/101.325 kPa

1.48 atm = Z

Thus, 150 kPa is equivalent to 1.48 atmospheres

You might be interested in
3. Examine the chemical formulas for the Arrhenius acids in Model 1. What feature do all the
Nostrana [21]

Answer:

They all have a hydrogen written separatly towards the beginning of the formula.

Explanation:

If you look at the Arrhenius acid formulas, you can see they all contain a hydrogen (H) at the beginning of them.

8 0
4 years ago
The six kingdom system was designed
KonstantinChe [14]

Answer:

Prokaryotes is the answer

hope it helped

3 0
4 years ago
Given that E°red = -0.40 V for Cd2+/Cd at 25°C, find E° and E for the concentration cell expressed using shorthand notation belo
tensa zangetsu [6.8K]

From the information in the question, the  E° and E for the cell is 0.00 V and 0.12 V.

Using the Nernst equation;

Ecell =  E°cell - 0.0592/n log Q

We know that  E°cell = 0.00 V since the anode and cathode are both made up of cadmium.

Substituting the given values into the Nernst equation;

Ecell = 0.00 V - 0.0592/2 log (1.0 × 10-5 M/0.100 M)

Ecell =  0.00 V - 0.0296 log(1 × 10^-4)

Ecell = 0.12 V

Learn more: brainly.com/question/8646601

3 0
3 years ago
0.378g grams of a compound is made up of 0.273g of Mg and 0.105g nitrogen. Find its empirical formula.
Harrizon [31]

Answer:

The empirical formula of the compound is Mg_3N_2.

Explanation:

Mass of magnesium in compound = 0.273 g

Mass of nitrogen in the compound = 0.105 g

Moles of magnesium =\frac{0.273 g}{24.305 g/mol}=0.0112 mol

Moles of nitrogen = \frac{0.105 g}{14.0067 g/mol}=0.00750 mol

Form empirical formula divides the lowest value of moles of an element present with all the moles of elements present.

Magnesium =\frac{0.0112 mol}{0.00750 mol}=1.5

Nitrogen =\frac{0.00750mol}{0.00750 mol}=1

The empirical formula of a compound:

Mg_{1.5}N_1=Mg_{\frac{15}{10}}N_1=Mg_{15}N_{10}=Mg_3N_2

The empirical formula of the compound is Mg_3N_2.

3 0
3 years ago
100 points PLEASEEE HELP ASAPPPP PLEASE Identify the kinds of bonds present between/among the given atoms/elements:
tresset_1 [31]

Answer:

20, 50, 25

Explanation:

I just figured it out somehow in my brain.

5 0
3 years ago
Other questions:
  • Identify the acid, base, conjugate acid and conjugate base in the following reactions:
    12·1 answer
  • What occurs when an atom loses an electron?
    12·1 answer
  • An experiment requires 15.0 ml of a 0.100 m solution of hcl. if you have a 12.0 m hcl stock solution in the laboratory, how woul
    15·1 answer
  • A mixture of oxygen, hydrogen, and nitrogen exerts a total pressure of 378 kPa. If the partial pressures of oxygen and hydrogen
    11·1 answer
  • Which of the following statements explain why the van der Waals equation must be used to describe real gases? X. interactions be
    11·1 answer
  • A solution at 25 degrees Celslus 1.0*10^ -5 MH 3 O^ + . What the concentration of OH^ - in this solution?
    15·1 answer
  • The weights of all elements are always compared to oxygen.
    9·1 answer
  • Which of the following elements has the lowest electron affinity?
    12·2 answers
  • What is the percent yield of a reaction that has a theoretical yield of 50.0 grams of product but after an experiment you only c
    13·1 answer
  • Which of the following is the correct way to do it for 3753 Scientific notation
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!