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Dominik [7]
3 years ago
10

Explain what you think the benefit to having wet earwax over dry earwax is.

Chemistry
1 answer:
hichkok12 [17]3 years ago
3 0
Healthy dry earwax does fall out of the ear better than wet earwax, and it is effective at preventing ear infections. However, it's still important to keep your ears clean because dry earwax flakes can build up over time and cause a blockage
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What percentage of carbon's orbitals are spherical in conformation?
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Orbitals are space around the nucleus where electrons orbit. Several orbitals can exist in a given energy level/shell. Carbon is the sixth element of the periodic table with 6 electrons. Carbon atoms have the ability to bond to themselves and to other atoms with sp, sp² and sp³, hybrid orbitals. Several orbitals in carbon are spherical conformation and this accounts to about 40% of the orbitals.
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Observe the concentrations of the hydronium ions(H3O+), hydroxide ions(OH-), and water (H2O) in the “Water Components” chart on
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3 years ago
Which atom would it be most difficult to remove an electron from
Norma-Jean [14]
I would be difficult to remove an electron from a Noble or Inert Gas (also known as the group 8 or 0 elements).  This is because they all have filled outermost shells and as such the outermost shell would be held tightly to the nucleus and as such make it difficult to remove.  Examples Helium, Neon, Argon, Xenon, Krypton and Radon 
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3 years ago
Muiltplying 2.5 x 10^10 by 3.5 x 10^-7
andrey2020 [161]

<u>Answer: </u>

The value of \left(2.5 \times 10^{10}\right) \times\left(3.5 \times 10^{-7}\right) is 8750

<u>Solution: </u>

\left(2.5 \times 10^{10}\right) \times\left(3.5 \times 10^{-7}\right)

\Rightarrow\left(2.5 \times 10^{10} \times 3.5 \times 10^{-7}\right)

\Rightarrow\left(2.5 \times 3.5 \times\left(10^{10} \times 10^{-7}\right)\right)

\Rightarrow(2.5 \times 3.5) \times\left(10^{10+(-7)}\right)

\Rightarrow(2.5 \times 3.5) \times\left(10^{10+(-7)}\right)

\Rightarrow(2.5 \times 3.5) \times 10^{3}

\Rightarrow 8.75 \times 10^{3}

\Rightarrow 8.75 \times 1000=8750

6 0
3 years ago
Calculate the Kelvin temperature to which 10.0 L of a gas at 27 °C would have to be heated to change the volume to 12.0 L. Units
KatRina [158]

Hello!

For this problem, we will be applying <em>Charles' Law</em>:

V1/T1 = V2/T2

Now that we have the formula, let's convert the temperature to Kelvin.

27 + 273 = 300K

Let's plug everything in now!

10/300 = 12.0/x

Simplified:

1/30 = 12.0/x

Cross-multiply:

1x = 30*12.0

<u>x = 360</u>

<em>Check!</em>

10/300 = 12/360

300*12 = 360*10

3600 = 3600

Therefore, you would have to heat the gas at a temperature of 360K in order to raise the volume to 12.0L.

 

4 0
3 years ago
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