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3 years ago

Explain what you think the benefit to having wet earwax over dry earwax is.

1 answer:

3 0

Healthy dry earwax does fall out of the ear better than wet earwax, and it is effective at preventing ear infections. However, it's still important to keep your ears clean because dry earwax flakes can build up over time and cause a blockage

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Biphenyl, C12H10,C12H10, is a nonvolatile, nonionizing solute that is soluble in benzene, C6H6.C6H6. At 25 ∘C,25 ∘C, the vapor p

cestrela7 [59]

Answer:

Vapour pressure of solution is 78.151 torr

Explanation:

Molar mass of biphenyl = 154.21 g

Molar mass of benzene = 78.11 g

19.2 g biphenyl = (19.2/154.21) moles of biphenyl = 0.125 moles of biphenyl

33.7 g of benzene = (33.7/78.11) moles of benzene = 0.431 moles of benzene

Total number of moles = (0.125+0.431) moles = 0.556 moles

Mole fraction of benzene in solution = (0.431/0.556) = 0.775

According to Roults law, vapour pressure of solution made from non-volatile solute = $(mole fraction of solvent in solution)\times (vapour pressure of pure solvent)$

Here solute is biphenyl and solvent is benzene

So, vapour pressure of solution = $(0.775\times 100.84)torr$ = 78.151 torr

8 0

3 years ago

How many molecules are in 48 grams of oxygen gas?

Alinara [238K]

Answer:

Since oxygen (O) has an atomic mass of 16 g, oxygen gas (O2) has a molecular mass of 2 x 16 = 32 g. We need to convert the given amount of oxygen gas to moles and this can be done by dividing the given mass by the molecular weight of oxygen gas. Hence, moles of oxygen gas = 48 g / 32 g/mole = 1.5 moles.

Explanation:

BARK BARK Hope it helps

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4 0

3 years ago

Read 2 more answers

How much positive charge is in 1.4 kg of oxygen? The atomic weight (15.9994 g) of oxygen contains Avogadro’s number of atoms, wi

Cerrena [4.2K]

Answer:

$6.7511\times 10^7\ C$

Explanation:

The atomic weight of oxygen = 15.9994 g

This mass corresponds to 1 mole of the oxygen atoms.

Thus,

15.9994 g mass of oxygen contains $6.02\times 10^{23}$ atoms of oxygen.

1.4 kg = 1400 g ( 1 kg = 1000 g)

So,

1400 g mass of oxygen contains $\frac {6.02\times 10^{23}}{15.9994}\times 1400$ atoms of oxygen.

Number of atoms in 1400 g of oxygen = $526.769754\times 10^{23}$

Also, 1 atom of oxygen contains 8 protons

Charge of 1 proton = + $1.602\times 10^{-19}\ C$

So, Charge on 1 atom of oxygen = $8\times 1.602\times 10^{-19}\ C$

Thus,

Charge on $526.769754\times 10^{23}$ atoms of oxygen = $526.94476\times 10^{23}\times 8\times 1.602\times 10^{-19}\ C=6.7533\times 10^7\ C$

Thus, positive charge in 1.4 kg of oxygen = $6.7511\times 10^7\ C$

5 0

3 years ago

A company sells a natural medicine with plant ingredients to help treat dementia, a disease in which people have a hard time rem

sammy [17]

I think it is the second one. hope it helps! :)

5 0

4 years ago

Read 2 more answers

Determine the number of unpaired electrons expected for [Fe(NO2)6]3−and for [FeF6]3− in terms of crystal field theory.

arsen [322]

Answer:

A. One unpaired electron

B. 5 unpaired electrons

Explanation:

In A ,Fe is in +3 oxidation state and Electronic configuration- [Ar]3d5

And NO2 is a strong field ligand hence it causes pairing in t2g orbitals and results one unpaired electron in dZX orbital.

In B, also Fe is in +3 oxidation state but F is weak field ligand hence causes no pairing of Electrons hence it results 5 unpaired electrons with electronic configuration t2g^3 eg^2

7 0

3 years ago