When placed in a container, the heaviest (most dense) will sink to the bottom and the lightest (least dense) will rise to the top.
Therefore, Gasoline would rise to the top.
First you need to calculate the number of moles of aluminium and copper chloride.
number of moles = mass / molecular weight
moles of Al = 512 / 27 = 19 moles
moles of CuCl = 1147 / 99 = 11.6 moles
From the reaction you see that:
if 2 moles of Al will react with 3 moles of CuCl
then 19 moles of Al will react with X moles of CuCl
X = (19 × 3) / 2 = 28.5 moles of CuCl, way more that 11.6 moles of CuCl wich is the quantity you have. So the copper chloride is the limiting reagent.
Answer:
15.5 moles
Explanation:
Applying,
PV = nRT.................. Equation 1
Where P = pressure, V = Volume, n = number of mole, R = molar gas constant, T = Temperature.
Make n the subject of the equation
n = PV/RT............... Equation 2
From the question,
Given: P = 0.899 atm, V = 425 L, T = 24 °C = (273+24) K = 297 K.
Constant: R = 0.083 L.atm/K.mol
Substitute these values into equation 2
n = (0.899×425)/(297×0.083)
n = 15.5 moles
I am going to assume that the reaction occurs in water since that is the easiest procedure (let me know if I am not supposed to make this assumption).
1) get 2 beakers, the chemicals for the reaction, DI water, and the catalyst.
2) equal volumes and amounts of the water was placed into the 2 beakers.
3) some of the catalyst was added to beaker the second beaker.
3) equal amounts of the chemicals for the reaction was placed into the 2 beakers.
4) the two reactions were compared to see how the un-catalyzed reaction in beaker 1 was effected by the introduction of a catalyst in beaker 2.
I hope this helps. Let me know in the comments if anything was unclear.
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