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ss7ja [257]
4 years ago
14

A water solution whose pH is 4_______. a. is always neutral b. is always acidic c. is always basic d. might be neutral, basic or

acidic.
Chemistry
2 answers:
polet [3.4K]4 years ago
7 0
C. Is Always Basic
 
<span>When pH < 7 the solution is acidic </span>
<span>When pH = 7 the solution is neutral </span>
<span>When pH > 7 the solution is basic</span>
sattari [20]4 years ago
7 0
<span>A water solution whose pH is 4 is always acidic. Acidic pH is always less than 7, that of greater than 7 is basic. The solution with  pH of 7 is called a neutral solution. pH is a measure of H+ concentration hence the acidic solutions have more H+ concentration</span>
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A potential energy diagram to illustrate this reaction mechanism is, assuming that the overall reaction is endothermic. Label re
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Use the concentration and rate data presented in the table below to answer the following questions about the hypothetical reaction:

A + 2B + 4C→ 2D + E


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3 0
3 years ago
Objects take on______ when they are lifted against the force of gravity to a position where they have the potential to fall.
Papessa [141]

A. because you haven't released the object so therefor the potential gravity force applied becomes actual when released.

8 0
3 years ago
Gold forms face-centered cubic crystals. The atomic radius of a gold atom is 144 pm. Consider the face of a unit cell with the n
kipiarov [429]

Answer:

The length of an edge of this unit cell is 407.294 pm

Explanation:

Face centered cubic structure contains 4 atoms in each unit cell and 12 coordination number, occupying about 74% volume of the total cell. Face centered cubic structure is known for efficient use of space for atom packing.

To determine the edge length, a relationship between the radius of the atom and edge length is used.

X = R√8

Where;

X is the length of an edge of this unit cell

R is the radius of the gold atom = 144 pm = 144 X 10⁻¹² m

X = 144 X 10⁻¹²√8

X = 407.294 X 10⁻¹² m

X = 407.294 pm

Therefore, the length of an edge of this unit cell is 407.294 pm

8 0
3 years ago
(part 1 of 3) Copper reacts with silver nitrate through a single replacement. If 1.29 g of silver are produced from the reaction
ale4655 [162]

Answer:

See explanation.

Explanation:

Hello there!

In this case, according to the described chemical reaction, we first write the corresponding equation to obtain:

Cu+2AgNO_3\rightarrow 2Ag+Cu(NO_3)_2

Thus, we proceed as follows:

Part 1 of 3: here, since the molar mass of silver and copper (II) nitrate are 107.87 and 187.55 g/mol respectively, and the mole ratio of the former to the latter is 2:1, we can set up the following stoichiometric expression:

m_{Cu(NO_3)_2}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu(NO_3)_2}{2molAg}*\frac{187.55gCu(NO_3)_2}{1molCu(NO_3)_2}   \\\\m_{Cu(NO_3)_2}=1.12gCu(NO_3)_2

Part 2 of 3: here, the molar mass of copper is 63.55 g/mol and the mole ratio of silver to copper is 2:1, the mass of the former that was used to start the reaction was:

m_{Cu}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu}{2molAg}*\frac{63.55gCu)_2}{1molCu}   \\\\m_{Cu}=0.380gCu

Part 3 of 3: here, the molar mass of silver nitrate is 169.87 g/mol and their mole ratio 2:2, thus, the mass of initial silver nitrate is:

m_{AgNO_3}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{2molAgNO_3}{2molAg}*\frac{169.87gAgNO_3}{1molAgNO_3}   \\\\m_{AgNO_3}=2.03gAgNO_3

Best regards!

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