Ask question

Ask question

All categories

3 years ago

9

NEED HELP PLEASE ONLY GOT 20 min

2 answers:

kirza4 [7]3 years ago

6 0

Step-by-step explanation:

i need the question

for the excellent

answer

Taya2010 [7]3 years ago

3 0

54, 45,90, 45, 45, 45

You might be interested in

Can anyone do this?

elixir [45]

The answer is Tuesday there will be 15 teachers for 179 students and 12 times 15 is 180

8 0

3 years ago

Read 2 more answers

5th grade math. correct answer will be marked brainliest

Gala2k [10]

Answer

c

Step-by-step explanation:

2.72 ÷ 1.54

5 0

3 years ago

Read 2 more answers

Alice needs to rent a car while on vacation. The rental company charges $17.95, plus 15 cents for each mile driven. If Alice onl

Readme [11.4K]

Answer:

Alice can drive 147 miles

Step-by-step explanation:

At first you subtract $17.95 from $40.

Then you are left with $22.05

Finally, you divide $22.05 by $0.15

And you get 147, so she can drive 147 miles without going over her limit.

7 0

3 years ago

A particular telephone number is used to receive both voice calls and fax messages. suppose that 20% of the incoming calls invol

Phoenix [80]

Answer:

0.1091 or 10.91%

Step-by-step explanation:

We have been given that a particular telephone number is used to receive both voice calls and fax messages. suppose that 20% of the incoming calls involve fax messages and consider a sample of 20 calls. We are asked to find the probability that exactly 6 of the calls involve a fax message.

We will use Bernoulli's trials to solve our given problem.

$P(X=x)=^nC_x\cdot P^x(1-P)^{n-x}$

$P(X=6)=^{20}C_6\cdot (0.20)^6(1-0.20)^{20-6}$

$P(X=6)=\frac{20!}{6!(20-6)!}\cdot (0.20)^6(0.80)^{14}$

$P(X=6)=\frac{20!}{6!(14)!}\cdot (0.000064)(0.04398046511104)$

$P(X=6)=38760\cdot (0.000064)(0.04398046511104)$

$P(X=6)=0.1090997009730$

$P(X=6)\approx 0.1091\\$

Therefore, the probability that exactly 6 of the calls involve a fax message would be approximately 0.1091 or 10.91%.

4 0

3 years ago

A marine aquarium has a small tank and a large tank, each containing only red and blue fish. In each tank, the ratio of red fish

Anna007 [38]

Answer:

Ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

Step-by-step explanation:

Let the number of red fish and blue fish in the large tank are x and y respectively.

Similarly ratio of red fish and blue fish in the small tank are x' and y' respectively.

Since in each tank ratio of the red fish to blue fish is 333 : 444

That means x : y = 333 : 444

Or $\frac{x}{y}=\frac{333}{444}$

⇒ $\frac{x}{y}=\frac{3}{4}$

⇒ y = $\frac{4x}{3}$ --------(1)

Similarly x' : y' = 333 : 444

⇒ $\frac{x'}{y'}=\frac{333}{444}$

⇒ $\frac{x'}{y'}=\frac{3}{4}$

⇒ x' = $\frac{3y'}{4}$ ------(2)

Ratio of the fish in large tank to the fish in small tank is 464646 : 555

So (x + y) : (x' + y') = 464646 : 555

$\frac{x+y}{x'+y'}=\frac{464646}{555}$

Now we replace the values of x and y' from equation (1) and equation (2)

$\frac{(x+\frac{4x}{3})}{(\frac{3y'}{4}+y')}=\frac{464646}{555}$

$\frac{\frac{7x}{3}}{\frac{7y'}{4}}=\frac{464646}{555}$

$\frac{4}{3}\times \frac{x}{y'}=\frac{464646}{555}$

$\frac{x}{y'}=\frac{3}{4}\times \frac{464646}{555}$

$\frac{x}{y'}=\frac{232323}{370}$

$\frac{y'}{x}=\frac{370}{232323}$

$\frac{y'}{x}=\frac{10}{6279}$

Therefore, ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

4 0

4 years ago