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inysia [295]
3 years ago
5

The elective courses for next year are gym, shop, art, consumer science, criminal justice, and computer science. Amber needs to

choose 3 electives. How many ways can she choose her electives
Mathematics
1 answer:
Nezavi [6.7K]3 years ago
3 0

Answer:

She can choose her electives in 20 ways.

Step-by-step explanation:

The order in which she chooses the courses is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

How many ways can she choose her electives?

3 electives from a set of 6. So

C_{6,3} = \frac{6!}{3!(6-3)!} = 20

She can choose her electives in 20 ways.

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Answer:x=4

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

4−3x=8−4x

4+−3x=8+−4x

−3x+4=−4x+8

Step 2: Add 4x to both sides.

−3x+4+4x=−4x+8+4x

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Step 3: Subtract 4 from both sides.

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