Answer:
Kinetic energy, E = 133.38 Joules
Explanation:
It is given that,
Mass of the model airplane, m = 3 kg
Velocity component, v₁ = 5 m/s (due east)
Velocity component, v₂ = 8 m/s (due north)
Let v is the resultant of velocity. It is given by :
![v=\sqrt{v_1^2+v_2^2}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7Bv_1%5E2%2Bv_2%5E2%7D)
![v=\sqrt{5^2+8^2}=9.43\ m/s](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B5%5E2%2B8%5E2%7D%3D9.43%5C%20m%2Fs)
Let E is the kinetic energy of the plane. It is given by :
![E=\dfrac{1}{2}mv^2](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7B1%7D%7B2%7Dmv%5E2)
![E=\dfrac{1}{2}\times 3\ kg\times (9.43\ m/s)^2](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%203%5C%20kg%5Ctimes%20%289.43%5C%20m%2Fs%29%5E2)
E = 133.38 Joules
So, the kinetic energy of the plane is 133.38 Joules. Hence, this is the required solution.
Answer:
The lethal voltage for the electrician under those conditions is 126.5 V.
Explanation:
To discover what is the lethal voltage to the electrician we need to find out what is the voltage that produces 55 mA = 0.055 A when across a resistance of 2300 Ohms (Electrician's body resistancy). For that we'll use Ohm's Law wich is expressed by the following equation:
V = i*R
Where V is the voltage we want to find out, i is the current wich is lethal to the electrician and R is his body resistance. By applying the given values we have:
V = 0.055*2300 = 126.5 V.
The lethal voltage for the electrician under those conditions is 126.5 V.
Answer:
Therefore the the highest frequency is 620Hz and lowest frequency is 580Hz
Explanation:
Given data
Source Frequency fs=600Hz
Length r=1.0m
RPM=100 rpm
The speed of the generator is calculated as:
![v_{s}=rw\\v_{s}=r(2\pi f)](https://tex.z-dn.net/?f=v_%7Bs%7D%3Drw%5C%5Cv_%7Bs%7D%3Dr%282%5Cpi%20f%29)
Substitute the given values
![v_{s}=(1.0m)2\pi (\frac{100}{60}rev/s )\\v_{s}=10.47m/s](https://tex.z-dn.net/?f=v_%7Bs%7D%3D%281.0m%292%5Cpi%20%28%5Cfrac%7B100%7D%7B60%7Drev%2Fs%20%29%5C%5Cv_%7Bs%7D%3D10.47m%2Fs)
For approaching generator the frequency is calculated as:
![f_{+}=\frac{f_{s}}{1-\frac{v_{s}}{v} }\\f_{+}=\frac{600Hz}{1-\frac{10.47m/s}{343m/s} } \\f_{+}=620Hz](https://tex.z-dn.net/?f=f_%7B%2B%7D%3D%5Cfrac%7Bf_%7Bs%7D%7D%7B1-%5Cfrac%7Bv_%7Bs%7D%7D%7Bv%7D%20%7D%5C%5Cf_%7B%2B%7D%3D%5Cfrac%7B600Hz%7D%7B1-%5Cfrac%7B10.47m%2Fs%7D%7B343m%2Fs%7D%20%7D%20%5C%5Cf_%7B%2B%7D%3D620Hz)
On the other hand,for the receding generator,Doppler's effect is expressed as:
![f_{-}=\frac{f_{s}}{1+\frac{v_{s}}{v} }\\f_{-}=\frac{600Hz}{1+\frac{10.47m/s}{343m/s} } \\f_{-}=580Hz](https://tex.z-dn.net/?f=f_%7B-%7D%3D%5Cfrac%7Bf_%7Bs%7D%7D%7B1%2B%5Cfrac%7Bv_%7Bs%7D%7D%7Bv%7D%20%7D%5C%5Cf_%7B-%7D%3D%5Cfrac%7B600Hz%7D%7B1%2B%5Cfrac%7B10.47m%2Fs%7D%7B343m%2Fs%7D%20%7D%20%5C%5Cf_%7B-%7D%3D580Hz)
Therefore the the highest frequency is 620Hz and lowest frequency is 580Hz
1. Delta, is formed by constructive erosion.