Answer:
The weight of 3.45 moles of carbon dioxide has been 151.8 grams.
Moles can be calculated as the mass of solute present with respect to the molecular mass of the solute.
Moles can be expressed as:
Moles = \rm \dfrac{weight}{molecular\;weight}
molecularweight
weight
The molecular weight of carbon dioxide has been 44 grams/mol.
The given moles of carbon dioxide = 3.45 moles.
3.45 mol = \rm \dfrac{weight}{44\;g/mol}
44g/mol
weight
Weight of carbon dioxide = 3.45 \times× 44 grams
Weight of carbon dioxide = 151.8 grams.
The weight of 3.45 moles of carbon dioxide has been 151.8 grams.
IT will be easy to know how chemical reactions occur
It will helps to know the fundamental particles of an atom
0.3268 moles of PC15 can be produced from 58.0 g of Cl₂ (and excess
P4)
<h3>How to calculate moles?</h3>
The balanced chemical equation is
The mass of clorine is m(
) = 58.0 g
The amount of clorine is n() = m()/M() = 58/70.906 = 0.817 mol
The stoichiometric reaction,shows that
10 moles of yield 4 moles of 
;
0.817 of yield x moles of
n() = 4*0.817/10 = 0.3268 mol
To know more about stoichiometric reaction, refer:
brainly.com/question/14935523
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Ion-dipole forces
H2O has hydrogen bonding, which is a form of dipole-dipole forces, and NO3- is an ion, so the intermolecular attraction is ion-dipole.
Answer: Quantitative data
Explanation:
