Using the law of constant proportions which says that within the same compound, elements exist in fixed ratios.
Therefore; we can use the ratio of total mass to the mass of carbon, to determine the amount of carbon in another sample.
Mass C / Mass CH4 = Mass C / Mass CH4
43.2 g / 57.6 g = Mass C / 37.8 g
Mass C = 37.8 g × 43.2 g / 57.6 g
= 28.35 g
Hence; the percentage of carbon will be;
=(28.35/ 37.8 )× 100%
= 75 %
Thus; 75% of 37.8 g of methane is carbon
The answer is D: Products combine to produce new reactants... Hope this helps! :)
The specific heat is the amount of heat per unit mass required to raise the temperature to 1 degree Celsius. (This is from google)
Answer:
E
Explanation:
A catalyst is a substance which alters the rate of a chemical reaction. We check for the correctness of each of the options as follows:
A. Is wrong.
A catalyst can increase the rate of the forward and backward reaction
B. Is wrong
A catalyst does not slow the reverse reaction only. This particular case is the case of a negative catalyst
C is wrong
A catalyst has no effect on the equilibrium nor the equilibrium constant
D is wrong
Catalyst has no effect on equilibrium value
E is correct
Although Catalysts has no effect on equilibrium or its constant value, it can increase the the rate at which equilibrium is achieved by speeding up the reaction through bringing down the activation energy
according to shape, size, and their relationship to surrounding layers of rock
Explanation:
Scientists classify intrusive features according to their shape, size and relationship to surrounding layers of rocks.
Intrusive igneous features are the sills, di/kes, batholith, laccoiith, lopolith e.t.c
- When magma cools and solidifies within the earth crust, they form intrusive igneous rocks.
- Intrusive igneous rocks differs from one another in their shape, size and relationship to surrounding rocks.
- For example, batholith is a large intrusive body that extends for several kilometers in the earth surface.
- Sills and di/kes are smaller bodies. Sills forms parallel to orientation of rocks in an area. Di/kes are known to cut across the orientation.
Learn more:
Sedimentary rocks brainly.com/question/2740663
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