Answer: Yes because that's when they form a compound
Answer:
See Explanation
Explanation:
Let us recall that;
[H^+] [OH^-] = 1 * 10^-14
Where;
[OH^-] = 1 x 10^-11
Then;
[H^+] = 1 * 10^-14/1 x 10^-11
[H^+] = 1 * 10^-3
pH = -log [H^+]
pH = -log(1 * 10^-3)
pH = 3
Also;
pH + pOH = 14
pOH = 14 - pH
pOH = 14 -3
pOH = 11
Answer:
The outside temperature is -45.8°C
Explanation:
When a gas keeps on constant its moles and its pressure, we can assume that volume will be increased or decreased as the T° (absolute T° in K).
V1 / T1 = V2 / T2
2.95L/298K = 2.25L / T2
(2.95L/298K ) . T2 = 2.25L
T2 = 2.25L . 298K / 2.95L
T2 = 227.2K
T°K - 273 = T°C
227.2K - 273 = -45.8°C
Answer:
47,9 kJ/g
Explanation:
The enthalpy of combustion is the change in energy due the reaction of combustion of n-octane. If the enthalpy is -4,79x10⁷ J/kg And knowing (1000J = 1kJ) (1000g = 1kg). The enthalpy of combustion expressed in kJ/g is:
= <em>47,9kJ/g</em>
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I hope it helps!
Answer:
Percentage composition = 14.583%
Explanation:
In chemistry, the emprical formular of a compound is the simplest formular a compound can have. It shows the simplest ratio in which the elements are combined in the compound.
Percentage composition by mass of Nitrogen
Nitrogen = 14g/mol
In one mole of the compound;
Mass of Nitrogen = 1 mol * 14g/mol = 14g
Mass of compound = 1 mol * 96.0 g/mol = 96
Percentage composition of Nitrogen = (Mass of Nitrogen / Mass of compound) * 100
percentage composition = 14/96 * 100
Percentage composition = 0.14583 * 100
Percentage composition = 14.583%
