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2 years ago

How are the amplitude and energy of a wave related

Physics

2 answers:

vovangra [49]2 years ago

4 0

B is most likely the answer (Wave amplitude and energy are not related)

In-s [12.5K]2 years ago

3 0

I would go with the last two because they are the same please give me brainiest if i am right

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Consider two waves X and Y traveling in the same medium. The two carry the same amount of energy per unit time, but X has one-se

RideAnS [48]

Answer:

7 / 1

Explanation:

The ratio of their amplitude = one-seventh and the ratio of their amplitude = the ratio of their wavelength

Ax / Ay = λx / λy = 1 / 7

λy / λx = 7 / 1

7 0

2 years ago

Knowing Newton’s 2nd Law, how would you rearrange it to solve for acceleration.

AysviL [449]

Answer:

Force / mass

Explanation:

Divide mass on both sides to get acceleration by itself leaving you with mass below force hence divide force by mass

8 0

2 years ago

Read 2 more answers

An object travels 7.5 m/s toward the west . Under the influence of a constant net force of 5.2 kN, it comes to rest in 3.2 s. Wh

Softa [21]

Answer:

m = 2218.67 kg

Explanation:

It is given that,

Initial velocity, u = 7.5 m/s

Final speed of an object, v = 0 (at rest)

Force, F = 5.2 kN

Time, t = 3.2 s

We need to find the mass of the object. Force acting on an object is given by :

F = ma

m is mass, a is acceleration

$F=\dfrac{m(v-u)}{t}\\\\m=\dfrac{Ft}{v-u}\\\\m=\dfrac{5.2\times 10^3\times 3.2}{0-7.5}\\\\m=2218.67\ kg$

So, the mass of the object is 2218.67 kg

5 0

2 years ago

If the out come of a 1.0-kg ball moving at 3.0 m/s is 4.5 kinetic energy what would the kinetic energy be if the mass and speed

Flauer [41]

Answer: KE = 36 J

Explanation: Solution:

KE = 1/2 mv²

= 1/2 ( 2 kg)(6 m/s)²

= 36 J

7 0

2 years ago

a marble rolls horizontally off a table that is 0.8m tall. if the marble lands 0.6m from the base of the table, what is the init

nignag [31]

The initial velocity of the marble from the given position is 1.49 m/s.

The given parameters;

height of the table, h = 0.8 m
horizontal distance traveled by the train, X = 0.6 m

The time of motion of the marble from the given height is calculated as;

$h = v_yt + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 0.8}{9.8} }\\\\t = 0.404 \ s$

The initial horizontal velocity of the marble is calculated as follows;

$X = v_0_xt\\\\v_0_x = \frac{X}{t} \\\\v_0_x = \frac{0.6}{0.404} \\\\v_0_x = 1.49 \ m/s$

Thus, the initial velocity of the marble from the given position is 1.49 m/s.

Learn more here:brainly.com/question/21180604

5 0

2 years ago