- Speed of the mobile = 250 m/s
- It starts decelerating at a rate of 3 m/s²
- Time travelled = 45s
- Velocity of mobile after 45 seconds
We can solve the above question using the three equations of motion which are:-
- v = u + at
- s = ut + 1/2 at²
- v² = u² + 2as
So, Here a is acceleration of the body, u is the initial velocity, v is the final velocity, t is the time taken and s is the displacement of the body.
We are provided with,
- u = 250 m/s
- a = -3 m/s²
- t = 45 s
By using 1st equation of motion,
⇛ v = u + at
⇛ v = 250 + (-3)45
⇛ v = 250 - 135 m/s
⇛ v = 115 m/s
✤ <u>Final</u><u> </u><u>velocity</u><u> </u><u>of</u><u> </u><u>mobile</u><u> </u><u>=</u><u> </u><u>1</u><u>1</u><u>5</u><u> </u><u>m</u><u>/</u><u>s</u>
<u>━━━━━━━━━━━━━━━━━━━━</u>
Distance= speed (multiplied by) time
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Answer:
Explanation:
When the two or more forces acting on a body such tat the net force on the body or the acceleration of the body is zero, then such forces are balanced forces.
For example, in the game of tug of war, both the teams pulls the rope with same force but in opposite directions so that the net acceleration is zero it means a balanced force is acting on the rope.
When tow or more forces acting on a body and there is some net force or acceleration of the body, then the forces are said to be unbalanced.
For example, if we push a box along the plane, the net force is non zero and the forces are unbalanced.
