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jeka57 [31]
3 years ago
14

How does the Doppler effect cause a siren's pitch to increase as it approaches you?

Physics
1 answer:
Lina20 [59]3 years ago
4 0

Answer:

Its C

a p e x approved

Explanation:

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A 0.100 kg ball hangs from a spring of negligible mass. When the ball is hung on the spring and is at rest, the spring is stretc
anzhelika [568]

Answer:

a) 4.9 N/m

b) 1.4 m/s

c) 0.225 s

Explanation:

Hooke's law states that

F = k * Δx

Where

F: force applied to a spring

k: constant of the spring

Δx: elongation of the spring

The force applied in this case is the weight of the ball, this is

P = m * g = 0.1 kg * 9.81 m/s^2 = 0.981 N

Rearrainging Hooke's law:

k = F / Δx

k = 0.981 / 0.2 = 4.9 N/m

If the ball is pulled down the spring will acquire some potential energy, when it is released, the potential energy will be released as kinetic energy on the ball

Ec = \frac{1}{2} * m * v^2

Elastic potential energy is:

U = \frac{1}{2} * k * \Delta x^2

The energy gained from the 0.2m pull will be turned into kinetic energy

Ec = U

Therefore:

\frac{1}{2} * m * v^2 = \frac{1}{2} * k * \Delta x^2

Rearranging:

v^2 = \frac{k}{m} * \Delta x^2

v = \Delta x * \sqrt{\frac{k}{m}}

v = 0.2 * \sqrt{\frac{4.9}{0.1}} = 1.4 m/s

After being released the ball will oscillate at the natural frequency of the system, which is

f = \frac{1}{2 * \pi} * \sqrt{\frac{k}{m}}

And the period will be:

T = 2 * \pi * \sqrt{\frac{m}{k}}

The period in this case is:

T = 2 * \pi * \sqrt{\frac{0.1}{4.9}} = 0.9 s

The ball will move up and down taking T time to complete a cycle, the movement from the stretched position to the equilibrium position takes T/4 = 0.225 s

8 0
3 years ago
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