Answer:
the atomic number is 11 and element is Sodium (Na)
Explanation:
Number of Protons = Number of Electrons = 11
Number of Neutrons = 13
Here, the Number of Protons and Number of Electrons is 11
So,
the atomic number is <em><u>11</u></em> and element is <em><u>Sodium </u></em><em><u>(</u></em><em><u>Na) </u></em>
There can be two cases
Case 1:
When a molecule has one carbon-carbon double bond and four monovalent atoms or groups in which two atoms on same carbon are different, there will be 2 isomers, one cis and one trans.
Case 2:
When a molecule has one carbon-carbon double bond and four monovalent atoms or groups where both atoms attached to the same carbon are same, there will be no geometrical isomerism.
As based on priority, there will be only two orientations possible , in which same priority atoms are on the same side that is cis and if they are on the opposite side that is trans.
Answer:
Explanation:
All the colligatives properties are modified by the Van't Hoff factor. This is shown as i, in the formula of the colligative properties freezing point depression, boiling point elevation, and osmotic pressure.
The Van't Hoff factor shows the number of particles into which the solute dissociates. In organic compounds we use 1, in inorganic compounds we have to think the dissociation. For example in aquous solutions, inorganic salts as AgNO₃ and CaCl₂ dissociate like this:
AgNO₃ → Ag⁺ + NO₃⁻
CaCl₂ → Ca²⁺ + 2Cl⁻
AgNO₃ has 2 moles of ions and CaCl₂ has 3 moles.
In urea: i = 1
In silver nitrate: i = 2
In calcium chloride: i = 3
The i = 3 for calcium chloride, makes that this salt has the highest osmotic pressure, highest vapor pressure and highest boiling point.
When entering a science lab which of the following should be done by science students.
D. Students must wait for their teacher to give instructions.
6. 20.0 x 17.16= 343.2m^2
Answer: The percent ionization of a monoprotic weak acid solution that is 0.188 M is 
Explanation:
Dissociation of weak acid is represented as:
cM 0 0
So dissociation constant will be:
Give c= 0.188 M and 
= ?
Putting in the values we get:
Thus percent ionization of a monoprotic weak acid solution that is 0.188 M is
