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2 years ago

14

Move the red arrow onto the picture to show how you think warm air would move over this area of land and water on a dark cold ni

ght.
Move the blue arrow onto the picture to show how you think cold air would move over this area of land and water on a dark cold night.

2 answers:

Bess [88]2 years ago

7 0

There’s no pictures?

Rus_ich [418]2 years ago

6 0

Where is the picture?

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A common carnival ride, called a gravitron, is a large r = 11 m cylinder in which people stand against the outer wall. the cylin

Leya [2.2K]

Answer:

v = 13.19 m / s

Explanation:

This problem must be solved using Newton's second law, we create a reference system where the x-axis is perpendicular to the cylinder and the Y-axis is vertical

X axis

N = m a

Centripetal acceleration is

a = v² / r

Y Axis

fr -W = 0

fr = W

The force of friction is

fr = μ N

Let's calculate

μ (m v² / r) = mg

μ v² / r = g

v² = g r / μ

v = √ (g r /μ)

v = √ (9.8 11 / 0.62)

v = 13.19 m / s

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3 years ago

bA cylinder is submerged in water as illustrated in the diagram. Which of the following statements is true? The pressure at B is

ozzi

Question: A cylinder is submerged in water as illustrated in the diagram. Which of the following statements is true?

Answer: The pressure at D is less than at B.

Explanation: this is because B has less amount of pressure and D has a lot more pressure weighing it down and B has less pressure

question answered by

(jacemorris04)

3 0

3 years ago

Read 2 more answers

A frictionless toy car is placed on a ramp, which is inclined at an unknown angle with respect to the horizontal. Starting from

NikAS [45]

The final speed of the toy car at the end of the given time period is 3.58 m/s.

The given parameters;

distance traveled by the car, s = 1.2 m
time of motion of the car, t = 0.67 s
initial velocity of the car, u = 0

The acceleration of the car is calculated as;

$s = ut + \frac{1}{2} at^2\\\\1.2 = 0 + 0.5\times a\times (0.67)^2\\\\1.2 = 0.225a\\\\a = \frac{1.2}{0.225} \\\\a = 5.33 \ m/s^2$

The final velocity of the toy car is calculated as;

$v_f^2 = u^2 + 2as\\\\v_f^2 = 0 + 2\times 5.33 \times 1.2\\\\v_f^2 = 12.792\\\\v_f = \sqrt{12.792} \\\\v_f = 3.58 \ m/s$

Thus, the final speed of the toy car at the end of the given time period is 3.58 m/s.

Learn more here: brainly.com/question/20352766

6 0

2 years ago

A train rolls to a stop along a horizontal track without the conductor applying the brakes. What answer choice BEST explains why

Naya [18.7K]

Answer:

B

Explanation:

Friction always eventually stops whatever is in motion.

4 0

3 years ago

0.22 L of pancake syrup has a mass of 33 g.

katrin2010 [14]

Answer:

a. 150 g/L

b. 75 g

c. 120 mL

Explanation:

a. 33g/0.22L=150 g/L

b. 33g/0.22L=150 g/L

150 g/L*0.5L=75g

c. 0.22L/33g=0.006667L/g

0.006667L/g*18g=0.12L

0.12L*1000=120mL

6 0

3 years ago