Answer:
step 2
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The effort force is the force applied to a machine. Work input is the work done on a machine. The work input of a machine is equal to the effort force times the distance over which the effort force is exerted.
Answer:
36 mol H
Explanation:
1 molecule C₆H₁₂O₆ contains 12 H atoms
1 mol C₆H₁₂O₆ contains 12 mol H atoms; Multiply by 3
3 mol C₆H₁₂O₆ contains 36 mol H atoms
If you are talking about moles of hydrogen molecules (H₂), you divide 36 by 2 and get 18 mol H₂.
Answer:
1.209g of MgO participates
Explanation:
In this problem, we have 0.030 moles of MgO that participates in a particular reaction.
And we are asked to solve for the mass of MgO that participates, that means, we need to convert moles to grams.
To convert moles to grams we need to use molar mass of the compound:
<em>1 atom of Mg has a molar mass of 24.3g/mol</em>
<em>1 atom of O has a molar mass of 16g/mol</em>
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That means molar mass of MgO is 24.3g/mol + 16g/mol = 40.3g/mol
And mass of 0.030 moles of MgO is:
0.030 moles MgO * (40.3g/mol) =
<h3>1.209g of MgO participates</h3>
Answer: 100.5cm³ and 100.5 mL
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