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3 years ago

Para que sirven las rondas?? ayuda por favor

Chemistry

1 answer:

prisoha [69]3 years ago

6 0

Answer:

las rondas sirven para ayudar con problemas matematicos asi como cilindros

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Ag+(aq) + e- → Ag(s) E° = +0.800 V AgBr(s) + e- → Ag(s) + Br-(aq) E° = +0.071 V Br2(l) + 2 e- → 2 Br-(aq) E° = +1.066 V Use some

Gekata [30.6K]

Answer:

$k_{sp}=4.7 \times 10^{-13}.$

Explanation:

Now equation of tqo halves are:

Oxidation : $Ag(s)-->Ag^+(aq)+e^-$

Reduction : $AgBr(s)+e^--->Ag(s)+Br^-(aq)$

We know,

$E^o_{cell}=0.071-(0.8)=-0.729\ V.$

$\Delta G^o=-n\times F \times E^o= -R\times T\times ln(k_s_p)\\-1\times 96485\times (-0.729)=-8.314\times 298\times ln(k_s_p)\\k_s_p=4.7\times 10^{-13}.$

$k_{sp}=4.7 \times 10^{-13}.$

Hence, this is the required solution.

5 0

3 years ago

Which type of radioactive decay does not produce any particles?

natta225 [31]

The answer is is gamma as alpha an beta both result in the release of a particle

3 0

3 years ago

Hydrogen atoms absorb energy so that the electrons are excited to n=4. Calculate the wavelength, in

FromTheMoon [43]

Answer:

the wavelength, in nm, of the photon is 487.5 nm

Explanation:

Given:

n = 4 (excited)

n = 2 (relaxes)

Question: Calculate the wavelength, in nm, λ = ?

First, it is important to calculate the energy of the electron when it excited and then when it relaxes.

$E_{1} =\frac{-13.6}{n^{2} } =\frac{-13.6}{4^{2} } =-0.85eV$ (excited)

$E_{2} =\frac{-13.6}{2^{2} } =-3.4eV$ (relaxes)

The change of energy

ΔE = E₁ - E₂=-0.85 - (-3.4) = 2.55 eV = 4.08x10⁻¹⁹J

For a photon, the wavelength emitted

$\lambda =\frac{hc}{delta(E)}$

Here

h = Planck's constant = 6.63x10⁻³⁴J s

c = speed of light = 3x10⁸m/s

Substituting values:

$\lambda =\frac{6.63x10^{-34}*3x10^{8} }{4.08x10^{-19} } =4.875x10^{-7} m=487.5nm$

8 0

2 years ago

PLZ HELP (SCIENCE) Match the following items.

FromTheMoon [43]

Oxidation: a chemical change resulting form a reaction with oxygen
Endothermic:a reaction that takes in energy
Exothermic: a reaction that releases energy
Decomposition:chemical change whereby a molecule breaks down into simpler moles clues or elements
Subscript:written underneath or below

6 0

2 years ago

Read 2 more answers

Predict whether each of the following bonds is ionic, polar, covalent, or nonpolar covalent:

Gekata [30.6K]

Explanation:

It is known that in order to determine a compound to be ionic, polar, covalent or non-polar covalent it is necessary to determine the electronegativity difference of the combining atoms.

So, when electronegativity difference is from 0.0 to 0.4 then bond formed between the two atoms is non-polar covalent in nature.

When electronegativity difference is greater than 0.4 and less than 1.8 then bond between the two atoms is a polar covalent bond.

When electronegativity difference is 1.8 or greater than the bond formed is ionic in nature.

Electronegativity difference of the given molecules is as follows.

Si-O = (1.90 - 3.44) = 1.54

K-Cl = (0.82 - 3.16) = 2.34

S-F = (2.58 - 3.98) = 1.4

P-Br = (2.19 - 2.96) = 0.77

Li-O = (0.98 - 3.44) = 2.46

N-P = (3.04 - 2.19) = 0.85

Therefore, given compounds are classified as follows.

Si-O, S-F, P-Br, and N-P all have a polar covalent bond. Whereas K-Cl and Li-O are ionic in nature.

7 0

3 years ago

Read 2 more answers