Answer:
2
Explanation:
Since you are balancing the equation you need to have equal amounts of each element on each side. Right now there is 2n and 2o on one side, and on the other 2n and 1o. Although the number of n's on each side is equal the number of o's are not. First I balance the number of oxygen's on each below, but doing that made the number of nitrogen's unbalanced. So then I balanced the nitrogens in step 2.
__N2+ __O2 = __N2O
1. __N2+ __O2 = 2 N20
2. 2 N2 + 1 O2 = 2 N2O
If it is in pure form, then only one type of atom. Negating if it has partially oxidized
Answer:
32.0 kJ
General Formulas and Concepts:
<u>Thermochemistry</u>
Specific Heat Formula: q = mcΔT
- q is heat (in J)
- m is mass (in g)
- c is specific heat (in J/g °C)
- ΔT is change in temperature (in °C)
Explanation:
<u>Step 1: Define</u>
<em>Identify variables</em>
[Given] <em>m</em> = 1.00 g
[Given] ΔT = 1.48 °C
[Given] <em>c</em> = 21.6 kJ/g °C
[Solve] <em>q</em>
<em />
<u>Step 2: Find Heat</u>
- Substitute in variables [Specific Heat Formula]: q = (1.00 g)(21.6 kJ/g °C)(1.48 °C)
- Multiply [Cancel out units]: q = (21.6 kJ/°C)(1.48 °C)
- Multiply [Cancel out units]: q = 31.968 kJ
<u>Step 3: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
31.968 kJ ≈ 32.0 kJ
Answer:
kilograms
Explanation:
hope this helps, pls mark brainliest :D