What major product is formed when heptyne is treated with Br2 in CCl4?
2 answers:
<u>Answer: </u>
<em>Option A is the Answer. </em>
<u>Explanation:</u>
Treatment of alkyne with Bromine in the presence of produces a trans product that is, a alkenyl bromide.
E-1, 2-dibromoheptene
It is a trans intermediate on further halogenations produces a tetrabromopentane.
It is an electrophilic expansion response in which the triple bond breaks to turn into a twofold bond and creates a dibromoalkene (E-1,2 dibromoheptene), and on further expansion, the twofold bond turns into a solitary bond and delivers a tetrabromoalkane.
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Answer:
The standard enthalpy of formation of methanol is, -238.7 kJ/mole
Explanation:
The formation reaction of CH_3OH will be,
The intermediate balanced chemical reaction will be,
..[1]
..[2]
..[3]
Now we will reverse the reaction 3, multiply reaction 2 by 2 then adding all the equations, Using Hess's law:
We get :
..[1]
..[2]
[3]
The expression for enthalpy of formation of will be,
The standard enthalpy of formation of methanol is, -238.7 kJ/mole