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AnnyKZ [126]
3 years ago
11

What major product is formed when heptyne is treated with Br2 in CCl4?

Chemistry
2 answers:
melisa1 [442]3 years ago
8 0

<u>Answer: </u>

<em>Option A is the Answer. </em>

<u>Explanation:</u>

Treatment of alkyne with Bromine in the presence of CCl_4 produces a trans product that is, a alkenyl bromide.

CH_3 \ CH_2 \ CH_2 \ CH_2 \ CH_2 - C = CH \frac {(CCl_4)}{(Br_2 )} >  CH_3 \ CH_2 \ CH_2\ CH_2 \CH_2\ -CBr = CHBr

E-1, 2-dibromoheptene

It is a trans intermediate on further halogenations produces a tetrabromopentane.  

It is an electrophilic expansion response in which the triple bond breaks to turn into a twofold bond and creates a dibromoalkene (E-1,2 dibromoheptene), and on further expansion, the twofold bond turns into a solitary bond and delivers a tetrabromoalkane.

ANTONII [103]3 years ago
4 0

Answer:A 1,2-dibromoheptene

Explanation:

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