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3 years ago

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352L of chlorine under a pressure of 680. mm Hg are placed in a container under a pressure of 1210 mm Hg. The temperature remain

s constant at 296 K. What is the volume of the container in liters?

1 answer:

Law Incorporation [45]3 years ago

8 0

Answer:

P1 = 680. mm P2 = 1210 mm

V1 = 352 mL V2 = ?

P1V1 = P2V2

V2 = P1V1/P2

V2 = 680. mm x 352 mL/1210 mm = 198 mL Cl2

Explanation:

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Concentrated hydrochloric acid is 36% (Weight/Volume) hydrochloric acid and has a density of 1.18 g.cm -3.

dezoksy [38]

The concentration refers to the amount of substance that is contained in solution.

<h3>What is the concentration?</h3>

The concentration refers to the amount of substance that is contained in solution. We can be able to obtain the concentration of the raw acid by the use of the relation;

Co = 10pd/M

M = molar mass of the acid

p = percentage of the acid

d = density of the acid

Co = 10 * 36 * 1.18/36.5

Co = 11.6 M

Using the dilution formula;

C1V1 = C2V2

10 * 11.6 = C2 * 1000

C2 = 10 * 11.6/1000

C2 = 0.116 M

Using again;

C1V1 = C2V2

0.116 * 5 = C2 * 20

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C2 = 0.029 M

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2 years ago

a gas has a volume of 95 mL at a pressure of 930 torr. What volume will the gas occupy if the pressure is increased to 970 torr

PilotLPTM [1.2K]

Boyle's law is a gas law, stating that the pressure and volume of a gas have an inverse relationship, when temperature is held constant i.e PV = constant. Therefore, P1V1 = P2V2--(i) ( P1 = initial pressure, P2= final pressure, V1= initial volume, V2= final volume). P1=930 torr, P2= 970 torr, V1= 95 ml, V2=?. Put these values in equation (i), 930 torr x 95 ml = 970 torr x V2. Therefore, V2 = 91.08 ml.

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4 years ago

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Name given to the type of microscope that only has one lens.

NeTakaya

Answer:

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3 years ago

Carbon monoxide (CO) is a poisonous gas because it binds very strongly to the oxygen carrier hemoglobin in blood. A concentratio

velikii [3]

<u>Answer:</u> The amount of CO that is occupied in the room is $1.98\times 10^3L$

<u>Explanation:</u>

We are given:

Concentration of CO = $8.00\times 10^2ppm=800pm$ by volume

This means that $800\mu L\text{ or }800\times 10^{-6}$ of CO is present in 1 L of blood

To calculate the volume of cuboid, we use the equation:

$V=lbh$

where,

V = volume of cuboid

l = length of cuboid = 10.99 m

b = breadth of cuboid = 18.97 m

h = height of cuboid = 11.89 m

$V=10.99\times 18.97\times 11.89=2478.83m^3$

Converting this into liters, by using conversion factor:

$1m^3=1000L$

So, $2478.83m^3=2.479\times 10^6L$

Applying unitary method:

In 1 L of blood, the amount of CO present is $800\times 10^{-6}$

So, in $2.479\times 10^6L$ of blood, the amount of CO present will be = $\frac{800\times 10^{-6}}{1}\times 2.479\times 10^{6}=1983.2L=1.98\times 10^3L$

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(D): pH 2- pH 1 good luck

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