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2 years ago

What effect will be produced on a capacitor if the separation between the plates is increased

Physics

1 answer:

soldi70 [24.7K]2 years ago

7 0

It will decrease the capacitance because we know nothing about the charge.

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How much work will a machine with a power rating of 1.1 × 103 watts do in 2.0 hours?

lyudmila [28]

Answer:

Explanation:

8.1X10 to the power of 6 Joules.

7 0

2 years ago

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A thin, horizontal rod with length l and mass M pivots about a vertical axis at one end. A force with constant magnitude F is ap

katen-ka-za [31]

Answer:

The magnitude of the angular acceleration is α = (3 * F)/(M * L)

Explanation:

using the equation of torque to the bar on the pivot, we have to:

τ = I * α, where

I = moment of inertia

α = angular acceleration

τ = torque

The moment of inertia is equal to:

I = (M * L^2)/3

Also torque is equal to:

τ = F * L

Replacing:

I * α = F * L

α = (F * L)/I = (F * L)/((M * L^2)/3) = (3 * F)/(M * L)

8 0

3 years ago

What is a star's main fuel during its lifetime? A. hydrogen B. carbon C. helium D. oxygen

Flura [38]

<span>The star's main fuel during its lifetime is hydrogen. It is said that a star is composed of 97% hydrogen and 3% helium. Once the hydrogen of a star is gone, the star becomes old because it burns hydrogen during its lifetime.</span>

6 0

3 years ago

A playground merry-go-round has a mass of 120 kg and a radius of 1.80 m and it is rotating with an angular velocity of 0.400 rev

saw5 [17]

Answer:

The final angular velocity is rev/s is 0.293 rev/s.

Explanation:

Given;

mass of the merry-go-round, m₁ = 120 kg

radius of the merry-go-round, r = 1.8 m

initial angular velocity, ω = 0.4 rev/s

mass of the child, m₂ = 22 kg

Apply the principle of conservation angular momentum to determine the final angular velocity;

$I_i= I_f\\\\\frac{1}{2} m_1r^2 \omega _i = \frac{1}{2} m_1r^2 \omega _f + m_2r^2 \omega _f\\\\ \frac{1}{2} m_1r^2 \omega _i =( \frac{1}{2} m_1r^2 + m_2r^2 )\omega _f\\\\\omega _f = \frac{ \frac{1}{2} m_1r^2 \omega _i}{\frac{1}{2} m_1r^2 + m_2r^2} \\\\\omega _f = \frac{ \frac{1}{2} m_1 \omega _i}{\frac{1}{2} m_1 + m_2}\\\\\omega _f = \frac{0.5 \ \times \ 120\ kg \ \times \ 0.4\ rev/s}{0.5 \ \times 120\ kg \ \ + \ \ 22 \ kg} \\\\\omega _f = 0.293 \ rev/s\\$

Therefore, the final angular velocity is rev/s is 0.293 rev/s.

3 0

3 years ago

Waves that move the particles of the medium parallel to the direction in which the waves are traveling are called a. longitudina

Kamila [148]

Your answer is longitudinal waves.

4 0

3 years ago

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