Question

AT the amusement park, the Ferris wheel is located 95 feet east and 156 feet north of the entrance. The swings are located 23 feet west and 124 feet north of the entrance. If Jalen is standing exactly three-eights the distance from the Ferris wheel to the swings, to the nearest hundredth foot, find the direct distance between Jalen and the entrance.

Answer 1

Answer:

131.58 feet

Step-by-step explanation:

Let the coordinates of the entrance be (0, 0). Since the Ferris wheel is located 95 feet east and 156 feet north of the entrance, its coordinates are (95, 156). Also, the swings are located 23 feet west and 124 feet north of the entrance. The coordinates of the swings are (-23, 124).

So, we find the distance, d between the Ferris wheel and the swing using

d = √[(x₂ - x₁)² + (y₂ - y₁)²] where d is the distance between coordinates (x₁, y₁) and (x₂, y₂).

Now  (x₁, y₁) = (95, 156) and  (x₂, y₂) = (-23, 124)

So, d = √[(x₂ - x₁)² + (y₂ - y₁)²]

d = √[(-23 - 95)² + (124 - 156)²]

d = √[(-118)² + (-68)²]

d = √[13924 + 4624]

d = √18548

d = 136.191 feet

Since Jalen is standing exactly three-eights the distance from the Ferris wheel to the swings, his distance from the Ferris wheel is d' = 3d/8 = 3 136.191/8 = 51.072 feet ≅ 51.07 feet

We now calculate the distance d' of the Ferris wheel to the gate. Since the coordinates of the gate are (0, 0) and the coordinates of the Ferris wheel are (95, 156), we use

d" = √[(x₂ - x₁)² + (y₂ - y₁)²]

Now  (x₁, y₁) =  (0, 0)  and  (x₂, y₂) = (95, 156)

So, d" = √[(x₂ - x₁)² + (y₂ - y₁)²]

d" = √[(95 - 0)² + (156 - 0)²]

d" = √[95² + 156²]

d" = √[9,025 + 24,336]

d" = √33,361

d" = 182.65 feet

Now the direct distance, D between Jalen and the entrance is thus distance from Ferris wheel to entrance minus distance from Jalen to Ferris wheel =  d" - d'

= 182.65 feet - 51.07 feet

= 131.58 feet