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Lilit [14]
2 years ago
9

HELP ME THE WHOLE PAGE !!!! Someone help please

Chemistry
1 answer:
Deffense [45]2 years ago
7 0

Answer:

In the image below

Explanation:

Hope this helps you :)

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What is the percent composition by mass of sulfur in the compound MgSO4 (gram formula mass = 120 g/mol)?
slavikrds [6]

26.7% is the percent composition by mass of sulfur in a compound named magnesium sulfate. Explanation: Molar mass of compound = 120 g/mol.

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2 years ago
A 951g sample of carbon steel with a specific heat capacity of .49j is heated to 673k and quenched in oil. The steel cools to 52
nikdorinn [45]

Answer: all I know it’s not -31.5 for ppl taking the k12 test

Explanation: I took the test

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2 years ago
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ILL GIVE BRAINLIEST
Mice21 [21]

Answer:

Which of the following happens during a lunar eclipse?

Select one:

a. Earth casts a shadow on the moon.

<u>b. The moon casts a shadow on Earth. </u>

c. Earth stops revolving in its orbit.

d. Earth starts revolving around the moon.

Explanation:

7 0
3 years ago
A sample of CO2 weighing 86.34g contains how many molecules?
irakobra [83]

Answer:

1.181 × 10²⁴ molecules CO₂

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

86.34 g CO₂

<u>Step 2: Identify Conversion</u>

Avogadro's Number

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Convert</u>

<u />86.34 \ g \ CO_2(\frac{1 \ mol \ CO_2}{44.01 \ g \ CO_2} )(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2} ) = 1.18141 × 10²⁴ molecules CO₂

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig fig rules and round.</em>

1.18141 × 10²⁴ molecules CO₂ ≈ 1.181 × 10²⁴ molecules CO₂

4 0
3 years ago
Why is baking soda an ionic bond
Kaylis [27]
Because it is made up of sodium, a metal, and carbon, a nonmetal.

Hope I helped ♡
6 0
3 years ago
Read 2 more answers
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