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Lilit [14]
2 years ago
9

HELP ME THE WHOLE PAGE !!!! Someone help please

Chemistry
1 answer:
Deffense [45]2 years ago
7 0

Answer:

In the image below

Explanation:

Hope this helps you :)

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A 5.5 × 10–3 M solution of fluoroacetic acid, CH2FCOOH, has a pH of 2.57. What is the acid-dissociation constant, K a, of this a
lianna [129]

The acid dissociation constant is 1.3 × 10^-3.

<h3>What is acid-dissociation constant?</h3>

The acid-dissociation constant is a constant that shows the extent of dissociation of an acid in solution. We have to set up the reaction equation as shown below;

Let the acid be HA;

                  HA       +      H2O ⇄      H3O^+      +      A^-

since the pH of the solution is 2.57 then;

[H3O^+] = Antilog(-pH) = Antilog(-2.57) = 2.7 × 10^-3

We can see that; [H3O^+]  = [A^-] so;

Ka = (2.7 × 10^-3)^2/(5.5 × 10^–3)

Ka = 1.3 × 10^-3

Learn more about acid-dissociation constant: brainly.com/question/9728159

6 0
2 years ago
write the net ionic equation (including phases) that corresponds to Cu(ClO4)2(aq) + Na2CO3(aq)--------&gt;CaCO3(s) + 2NaClO4(aq)
soldier1979 [14.2K]
Complete ionic:
Cu(aq) + 2Cl(aq) + 8O(aq) + 2Na(aq) + C(aq) + 3O(aq) = CaCO3(s) + 2Na(aq) + Cl(aq) + 4O(aq) 

Net ionic:

Cu(aq) + Cl(aq) + 4O(aq) + 2Na(aq) + C(aq) + 3O(aq) = CaCO3(s) 

So write everything out as IF it will dissociate in water. So everything that is aq splits but solid just floats to the bottom of the mixture. Cancel what you can (in this case the two from the ClO4 on the left of the equation cancels with the ClO4 from the right) and the 2Na cancels. Then, write out the whole solution and you are done! 
3 0
2 years ago
The molarity of a 4.200 L solution is 1.230 M Na2CO3. What is the mass of Na2CO3
Lerok [7]

Answer:

547.5g

Explanation:

To get the mass, you need moles.

moles = (molarity)(Liters)

moles = (1.230M)(4.200L) = 5.166 moles Na2CO3

Now, just use stoichiometry

molar mass of Na2CO3 = 2(mass of Na) + (mass of C) + 3(mass of O)

= 2(22.9) + 12.01 + 3(16) = 105.99g/mol

5.166moles(105.99g/mol)

= 547.544

But, the measurements given had 4 significant figures, so in chemistry we write:

547.5g

7 0
3 years ago
If 1.20 moles of an ideal gas occupy a volume of 18.2 l at a pressure of 1.80 atm, what is the temperature of the gas, in degree
scoundrel [369]

We can calculate for temperature by assuming the equation for ideal gas law:

P V = n R T

Where,

P = pressure = 1.80 atm

V = volume = 18.2 L

n = number of moles = 1.20 moles

R = gas constant = 0.08205746 L atm / mol K

Substituting to the given equation:

T = P V / n R

T = (1.8 atm * 18.2 L) / (1.2 moles * 0.08205746 L atm / mol K)

T = 332.70 K

We can convert K unit to ˚C unit by subtracting 273.15 to Kelvin, therefore

T = 59.55 ˚<span>C</span>

6 0
3 years ago
What is the mass in grams of 0.280 mole sample of sodium hydroxide NaOH​
vivado [14]

Answer:

The mass of 0.280 mole sample of sodium hydroxide NaOH​ is 11.2 grams.

Explanation:

To know the mass in grams of 0.280 moles of sample of sodium hydroxide NaOH, you must know the molar mass of the compound, that is, the mass of one mole of a substance, which can be an element or a compound.

So you know:

  • Na: 23 g/mole
  • O: 16 g/mole
  • H: 1 g/mole

So, the molar mass of NaOH is:

NaOH= 23 g/mole + 16 g/mole+ 1 g/mole= 40 g/mole

Then the following rule of three can be applied: if in 1 mole of sodium hydroxide there are 40 grams, in 0.280 moles how much mass is there?

mass=\frac{0.28 moles*40 grams}{1 mole}

mass= 11.2 grams

<u><em>The mass of 0.280 mole sample of sodium hydroxide NaOH​ is 11.2 grams.</em></u>

4 0
3 years ago
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