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2 years ago

Scientists will often use a(n) _________________, an object that helps explain ideas about the natural world.

Chemistry

2 answers:

Nadya [2.5K]2 years ago

7 0

Scientists will often use a(n) _________________, an object that helps explain ideas about the natural world.

The answer is model.

sweet-ann [11.9K]2 years ago

4 0

Answer:

model

Explanation:

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If a sample of N2 gas has an initial pressure of 500 Torr and volume of 0.5 L, what will the final volume be if the pressure is

kherson [118]

Answer:

V₂ = 0.4 L

Explanation:

Data:

P₁ (initial pressure) = 500 torr
V₁ (initial volume) = 0.5 L
P₂ (final pressure) = 700 torr

Wanted:

V₂ (final volume)

Equation:

P₁V₁ = P₂V₂ → V₂ = P₁V₁ / P₂

Solution:

V₂ = $\frac{(500 torr)(0.5 L)}{700 torr}$ = 0.3571 L or 0.4 L

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2 years ago

Ernest Shackleton's South! primarily uses which writing structure?

damaskus [11]

Ernest Shackleton's South! primarily uses the writing structure of "problem and solution".

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2 years ago

How are silicate minerals different from nonsilicate minerals

tino4ka555 [31]

Answer: The main difference between silicate minerals and nonsilicate minerals is that silicate minerals are composed of silicate groups whereas Nonsilicate minerals have no silicate groups.

Explanation:

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2 years ago

How many moles of chlorine gas would occupy a volume of 35.5 L at a pressure of 100.0 kPa and a

Nikolay [14]

Answer:

this was the last of .the last 555543 years of 55my in

Explanation:

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2 years ago

The partial pressure of N2 in the air is 593 mm Hg at 1 atm. What is the partial pressure of N2 in a bubble of air a scuba diver

Evgen [1.6K]

Answer: Partial pressure of $N_{2}$ at a depth of 132 ft below sea level is 2964 mm Hg.

Explanation:

It is known that 1 atm = 760 mm Hg.

Also, $P_{N_{2}} = x_{N_{2}}P$

where, $P_{N_{2}}$ = partial pressure of $N_{2}$

P = atmospheric pressure

$x_{N_{2}}$ = mole fraction of $N_{2}$

Putting the given values into the above formula as follows.

$P_{N_{2}} = x_{N_{2}}P$

$593 mm Hg = x_{N_{2}} \times 760 mm Hg$

$x_{N_{2}}$ = 0.780

Now, at a depth of 132 ft below the surface of the water where pressure is 5.0 atm. So, partial pressure of $N_{2}$ is as follows.

$P_{N_{2}} = x_{N_{2}}P$

= $0.78 \times 5 atm \times \frac{760 mm Hg}{1 atm}$

= 2964 mm Hg

Therefore, we can conclude that partial pressure of $N_{2}$ at a depth of 132 ft below sea level is 2964 mm Hg.

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2 years ago