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LenKa [72]
3 years ago
11

The speed of sound in air is around 330 m/s. If a bat emits a single high-pitched ‘click’ of sound in a cave that is 25m wide, c

alculate the time taken for the echo of the sound to return to the bat.
Physics
1 answer:
Bingel [31]3 years ago
4 0

Answer:

0.15 s

Explanation:

From the question given above, the following data were obtained:

Speed of sound (v) = 330 m/s

Distance (x) = 25 m

Time (t) =?

The time taken for the echo of the sound to the bat can be obtained as follow:

v = 2x / t

330 = 2 × 25 / t

330 = 50 / t

Cross multiply

330 × t = 50

Divide both side by 330

t = 50 / 330

t = 0.15 s

Thus, it will take 0.15 s for the echo of the sound to the bat

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Answer:

The maximum power density in the reactor is 37.562 KW/L.

Explanation:

Given that,

Height = 10 ft = 3.048 m

Diameter = 10 ft = 3.048 m

Flux = 1.5

Power = 835 MW

We need to calculate the volume of cylinder

Using formula of volume

V =\pi r^2 h

Put the value into the formula

V=\pi\times(1.524)^2\times 3.048

V= 22.23\m^3

V = 22.23\times10^{3}\ Liter

We need to calculate the maximum power density in the reactor

Using formula of power density

P=\dfrac{E}{V}

Where, P = power density

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P=\dfrac{835\times10^{6}}{22.23\times10^{3}}

P=37561.85 = 37.562\times KW/L

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Explanation:

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In a river, sediment is deposited _____. on the inside bends on the outside bends by fast moving water by oxbows
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3 years ago
•• CP Two blocks connected by a light horizontal rope sit at rest on a horizontal, frictionless surface. Block AA has mass 15.0
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Answer:

(a) T= 38.4 N

(b) m= 26.67 kg

Explanation:

We apply Newton's second law:

∑F = m*a (Formula 1)

∑F : algebraic sum of the forces in Newton (N)

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

Kinematics

d= v₀t+ (1/2)*a*t² (Formula 2)

d:displacement in meters (m)  

t : time in seconds (s)

v₀: initial speed in m/s  

vf: final speed in m/s  

a: acceleration in m/s²

v₀=0, d=18 m , t=5 s

We apply the formula 2 to calculate the accelerations of the blocks:

d= v₀t+ (1/2)*a*t²

18= 0+  (1/2)*a*(5)²

a= (2*18) / ( 25) = 1.44 m/s² to the right

We apply Newton's second law to the block A

∑Fx = m*ax

60-T = 15*1.44

60 - 15*1.44 = T

T = 38.4 N

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∑Fx = m*ax

T = m*ax

38.4 = m*1.44

m= (38.4) / (1.44)

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4 years ago
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Upwarped mountain is created when rock layers are pushed up by forces inside the Earth.
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