Answer:
Plane will 741.6959 m apart after 1.7 hour
Explanation:
We have given time = 1.7 hr
So if we draw the vectors of a 2d graph we see that the difference in angles is = 
Speed of first plane = 730 m/h
So distance traveled by first plane = 730×1.7 = 1241 m
Speed of second plane = 590 m/hr
So distance traveled by second plane = 590×1.7 = 1003 m
We represent these distances as two sides of the triangle, and the distance between the planes as the side opposing the angle 58.6.
Using the law of cosine,
representing the distance between the planes, we see that:

r = 741.6959 m
Answer:
The force of the impact would be smaller
Explanation: Examples:
If the force is big then the time would be small (2500N of Force = 10 seconds)
If the force is small then the time would be big (250N of Force = 50 seconds)
Impulse/Collision -> [Ft] = [M (vf-vo)] <- Change in momentum
Answer:
since small stone has less mass so the gravitational pull of the earth is lesser in case of this but this is not for the bigger stone as the gravitational pull of the earth is greater...
PLEASE MARK BRAINLIEST!!!!!
Answer:
2.83m
Explanation:
The information that we have is
Intensity at 2.0 m:
and 
we need an intensity level of: 
thus, we are looking for the distance
.
which we can find with the law for intensity and distance:

we solve for
:

and we substitute the known values:

at a distance of 2.83m the intensity level is 40dB