To solve this problem we will apply the concepts related to Ohm's law and Electric Power. By Ohm's law we know that resistance is equivalent to,
Here,
V = Voltage
I = Current
While the power is equivalent to the product between the current and the voltage, thus solving for the current we have,
Applying Ohm's law
Therefore the equivalent resistance of the light string is 
Answer:
if the frequency is double, the wavelength is only half as long
Explanation:
Answer:
- 278.34 kg m/s^2
Explanation:
The rate of the change of momentum is the same as the force.
The force that an object feels when moviming in a circular motion is given by:
F = -mrω^2
Where ω is the angular speed and r is the radius of the circumference
Aditionally, the tangential velocity of the body is given as:
v = rω
The question tells us that
v = 25 m/s
r = 7m
mv = 78 kg m/s
Therefore:
m = (78 kg m/s) / (25 m/s) = 3.12 kg
ω = (25 m/s) / (7 m) = 3.57 (1/s)
Now, we can calculate the force or rate of change of momentum:
F = - (3.12 kg) (7 m)(3.57 (1/s))^2
F = - 278.34 kg m/s^2
Answer:
The answer to your question is Ke = 72 J
Explanation:
Kinetic energy depends on the speed of and object and its mass.
Data
mass = m = 4 kg
speed = v = 6 m/s
distance = d = 8 m
Kinetic energy = ke = ?
Formula
Ke = (1/2) mv²
Substitution
Ke = (1/2) (4)(6)²
Simplification
Ke = (1/2)(4)(36)
Ke = (1/2)(144)
Ke = 72 Joules
Result
Ke = 72 J
Explanation:it is beause they are sharper and also have less surface area and therefore more pressure
