Answer:
Solute is Pottasium Nitrate and Solvent is Water.
Explanation:
Ag can be used to remove lead from lead (II) nitrate.
Option C
<u>Explanation:</u>
In order to separate the lead from lead (II) nitrate, we have to react it with another solution having same oxidation state and which can replace lead and make it as a precipitate.
So among the given options, Ag has high tendency to react with nitrate easily. Since, the oxidation state of Ag is also similar to the oxidation state of Pb, it can easily substitute Pb. Thus, Ag can be used to remove lead from lead nitrate.
<em>Nitric acid, </em><em>is a highly corrosive mineral acid. The pure compound is colorless, but older samples tend to acquire a yellow cast due to decomposition into oxides of nitrogen and water.</em>
There are THREE different elements and a total of FIVE atoms in nitric acid.
<em>The formula for nitric acid is</em><em> </em><em><u>HNO3.</u></em><em> This means there is one atom of hydrogen, one atom of nitrogen, and three atoms of oxygen in one molecule of nitric acid.</em>
<em>So, Thus, your answer will be </em><u><em>FIVE</em></u><em> if you're counting the molecules but if you are counting the elements then it is </em><u><em>THREE.</em></u>
<em>-Snooky</em>
45.098 L
45098/1000 = 45.098
Answer:0.05M
Explanation:
Mass=12g
Volume in liters =3.2L
Molecular mass of KCL=1x39.0983+1x35.453=74.5513
Number of moles=mass ➗ molecular mass
Number of moles=12 ➗ 74.5513
Number of moles=0.16
Molarity=number of moles ➗ volume in liters
Molarity=0.16 ➗ 3.2
Molarity=0.05M
