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Anika [276]
2 years ago
7

If you know all of the forces acting on a moving object, can you tell in which direction the object is moving? if the answer is

yes, explain how. If the answer is no, give an example.
Physics
1 answer:
Montano1993 [528]2 years ago
8 0

No, knowing all the forces is not enough to know the direction of motion.

<h3>How to use Newton's laws?</h3>

The second Newton's law states that:

F = m*a

This says <u><em>"force equals mass times acceleration".</em></u>

Where acceleration is the rate of change of the speed. From that equation, we conclude that the acceleration is in the same direction that the net force.

So, if we know all the forces acting on an object, we know the net force acting on it, then we know the direction of the acceleration.

<h3>Is this enough to know the direction in which it is moving?</h3>

No, the object does not need to move in the same direction than its acceleration, the direction of motion will also depend on the initial velocity of the object (if it is initially moving with constant speed).

If we don't know that, we can't find the direction of motion.

An example of this can be a car going at 100km/h east-wise.

Then we apply a net force due west, then we have an acceleration due west. But as the initial direction of motion was east, the car will still move to the east, but the velocity will decrease gradually.

So as you can see in that example, we need to know the initial velocity to know the direction in which the object is moving.

If you want to know more about acceleration, you can read:

brainly.com/question/605631

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A.900 watts That would be your correct answer 
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3 years ago
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The net force acting on an object equals the applied force plus the force of friction.
Georgia [21]

Answer:

False

Explanation:

The net force is equal to the applied force minus the force of friction. It is possible for friction to act in the same direction as an applied force, but that would mean there would have to be more than two forces acting on the object.

3 0
3 years ago
What is the most potentially destructive way to deal with stress while at college? a. texting friends back home b. watching TV c
diamong [38]

Answer:

Option (C)

Explanation:

Recreational drugs are usually referred to those drugs or medicines that are legally or illegally used without any prescription given by the doctors. These drugs include marijuana, cocaine, alcohol, nicotine, heroin, and many others. These drugs provide relaxation for a shorter period of time, but using of these substances, it makes an individual addicted to drugs.

So, recreational drugs are one of the most potentially destructive ways to handle stress when a student is in college.

Thus, the correct answer is option (C).

7 0
3 years ago
A crate is pushed horizontally by a horizontal force 527.018 N . Sliding friction resists the motion, and the kinetic coefficien
gulaghasi [49]

Answer:

m= 10 kg a = 52 m / s²

Explanation:

For this problem we must use Newton's second law, let's apply it to each axis

X axis

      F - fr = ma

The equation for the force of friction is

    -fr = miu N

Axis y

     N- W = 0

     N = mg

Let's replace and calculate laceration

     F - miu (mg) = ma

    a = F / m - mi g

    a = 527.018 / m - 0.17 9.8

We must know the mass of the body suppose m = 10 kg

    a = 527.018 / 10 - 1,666

    a = 52 m / s²

5 0
3 years ago
An electron moving parallel to a uniform electric field increases its speed from 2.0 × 10^7 m/s to 4.0 × 10^7 m/s over a distanc
julia-pushkina [17]

Answer:

E = 2.84 * 10^5 N/C

Explanation:

The speed increased from 2.0 * 10^7 m/s to 4.0 * 10^7 m/s over a 1.2 cm distance.

Let us find the acceleration:

v^2 = u^2 + 2as

(4.0 * 10^7)^2 = (2.0 * 10^7)^2 + 2 * a * 0.012\\\\(4.0 * 10^7)^2 - (2.0 * 10^7)^2 = 0.024a\\\\1.2 * 10^{15}= 0.024a\\\\a = 1.2 * 10^{15} / 0.024\\\\a = 5 * 10^{16} m/s^2

Electric force is given as the product of charge and electric field strength:

F = qE

where q = electric charge

E = Electric field strength

Force is generally given as:

F = ma

where m = mass

a = acceleration

Equating both:

ma = qE

E = ma / q

For an electron:

m = 9.11 × 10^{-31} kg

q = 1.602 × 10^{-19} C

Therefore, the electric field strength of the electron is:

E = \frac{9.11 * 10^{-31} * 5 * 10^{16}}{1.602 * 10^{-19}} \\\\E = 2.84 * 10^5 N/C

8 0
3 years ago
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