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Archy [21]
4 years ago
6

How much water remains unfrozen after 62.2 kJ is transferred as heat from 364 g of liquid water initially at its freezing point?

The latent heat of fusion is 333 kJ/kg.
Physics
1 answer:
Amanda [17]4 years ago
6 0

Answer:

177.213 grams

Explanation:

Given:

Total amount of water = 364 grams

Latent heat of fusion = 333 kJ/kg

Heat transferred = 62.2 kJ

The amount of water frozen = 62.2/333 = 0.186786 kg =  186.786 grams

Hence, the amount of water remained unfrozen = Total water - Amount of water frozen

the amount of water remained unfrozen = 364 grams - 186.786 grams = 177.213 grams

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Answer: What happens when the thermal energy of a substance increases is that D. Both the motion of the particles in the substance and the temperature of the substance increase.

Explanation: When thermal energy increases, it is due to particles moving faster. It also results in higher temperatures or heat.

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Which of the following is false?
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The correct answer is C
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his is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Air enters a nozzle steadi
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Answer:

his is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Air enters a nozzle steadily at 2.21 kg/m3 and 40 m/s and leaves at 0.762 kg/m3 and 192 m/s. The inlet area of the nozzle is 90 cm2.

determine (a) the mass flow rate through the nozzle, and (b) the exit area of the nozzle.

a)0.7956kg/s

b)5.437 × 10⁻³m²

Explanation:

The concepts related to the change of mass flow for both entry and exit is applied

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\dot{m}=\rho A V

Where,

\dot{m} = mass flow rate\\\rho = Density\\V = Velocity

values are divided by inlet(1) and outlet(2) by

\rho_1 = 2.21kg/m^3V_1 = 40m/s

A_1 = 90*10^{-4}m^2\\\rho_2 = 0.762kg/m^3\\V_2 = 192m/s

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\dot{m} = \rho_1 A_1 V_1\\\dot{m} = (2.21)(90*10^{-4})(40)\\\dot{m} = 0.7956kg/s

PART B) For the exit area we need to arrange the equation in function of Area, that is

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A person, with his ear to the ground, sees a huge stone strike the concrete pavement. A moment later two sounds are heard from t
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Answer:

The impact occured at a distance of 2478.585 meters from the person.

Explanation:

(After some research on web, we conclude that problem is not incomplete) The element "Part A" may lead to the false idea that question is incomplete. Correct form is presented below:

<em>A person, with his ear to the ground, sees a huge stone strike the concrete pavement. A moment later two sounds are heard from the impact: one travels in the air and the other in the concrete, and they are 6.4 seconds apart. How far away did the impact occur? (Sound speed in the air: 343 meters per second, sound speed in concrete: 3000 meters per second)</em>

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t_{A} - Time spent by the sound in the air, in seconds.

By suposing that sound travels the same distance and at constant speed in both materials, we have the following expression:

\Delta t = \frac{x}{v_{A}}-\frac{x}{v_{C}}

\Delta t = x\cdot \left(\frac{1}{v_{A}}-\frac{1}{v_{C}}  \right)

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x - Distance traveled by the sound, in meters.

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x = \frac{\Delta t}{\frac{1}{v_{A}}-\frac{1}{v_{C}}  }

x = 2478.585\,m

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