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3 years ago

Can you please tell me what this is

Physics

1 answer:

Anna [14]3 years ago

4 0

Answer:

200000 J

Explanation:

From the question given above, the following data were obtained:

Mass (m) of roller coaster = 1000 Kg

Velocity (v) of roller coaster = 20 m/s

Kinetic energy (KE) =?

Kinetic energy is simply defined as the energy possess by an object in motion. Mathematically, it can be expressed as:

KE = ½mv²

Where

KE => is the kinetic energy.

m =>is the mass of the object

V => it the velocity of the object.

With the above formula, we can obtain the kinetic energy of the roller coaster as follow:

Mass (m) of roller coaster = 1000 Kg

Velocity (v) of roller coaster = 20 m/s

Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 1000 × 20²

KE = 500 × 400

KE = 200000 J

Therefore, the kinetic energy of the roller coaster is 200000 J.

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Two blocks of clay, one of mass 1.00 kg and one of mass 3.00 kg, undergo a completely inelastic collision. Before the collision

enyata [817]

Answer:

The initial speed of the 1kg block is 8 m/s.

Explanation:

The question simply asks for the initial speed of the 1.00 kg block.

The initial kinetic energy of the 1kg block is = 32 Joules

Using this kinetic energy, and the equation below, we can find the speed of the 1kg block:

Kinetic Energy = $\frac{1}{2}m*v^2$

$32=\frac{1}{2}(1)*v^2$

$v = \sqrt{64}$

v = 8 m/s

The initial speed of the 1kg block is 8 m/s.

6 0

3 years ago

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A factory robot drops a 10 kg computer onto a conveyor belt running at 3.1 m/s. The materials are such that μs = 0.50 and μk = 0

frutty [35]

Answer:

x = 1.63 m

Explanation:

mass (m) = 10 kg

μk = 0.3

velocity (v) = 3.1 m/s

Assuming that most of the computers weight is applied on the belt instantaneously, we can apply the constant acceleration equation below

x = $v^{2}/2a$

where a = μk.g , therefore

x = $v^{2}$ /2μk.g

x = (3.1 x 3.1)/(2 x 0.3 x 9.8)

x = 1.63 m

8 0

3 years ago

Can some please help me

Brilliant_brown [7]

Answer:

Classification

– Drug (highly regulated)

§ A substance which changes body structure or function.

§ Stimulate hormone secretions

§ Looks like medicine and/or is administered differently than foods

– Dietary Supplement (not highly regulated)

§ Highly refined products

§ No positive nutritional value

Explanation:

https://web.cortland.edu/buckenmeyerp/Lecture14.html

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3 years ago

What is the time required for an object starting at rest to fall freely 500 meters near earth surface

Gnom [1K]

Using kinematics, approximately 10.1 seconds

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3 years ago

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A 200 kg boulder is 1000m above the ground. What is the speed of the object right before it hits the ground?

dem82 [27]

Answer:

$140.07m/s$

Explanation:

we use the equation for the final speed:

$v_{f}^2=v_{0}^2+2gh$

where $v_{f}$ is the final speed, $v_{0}$ is the initial speed, $g$ is the gravitational acceleration ( $g=9.81m/s^2$ ) and $h$ is the height.

In this case we don't have an initial velocity indicated so: $v_{0}=0$ , and we are told that the boulder is at a height: $h=1,000m$ .

We substitute this values into the equation:

$v_{f}^2=2gh\\v_{f}^2=2(9.81m/s^2)(1,000m)\\v_{f} ^2=19,620m^2/s^2\\\\v_{f}=\sqrt{19,620m^2/s^2} \\v_{f}=140.07m/s$

the speed of the object right before it hits the ground is $140.07m/s$

6 0

3 years ago