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Black_prince [1.1K]
3 years ago
13

If two point sources of light are being imaged by this telescope, what is the maximum wavelength λ at which the two can be resol

ved if their angular separation is 3.0×10−5 radians?
Physics
1 answer:
Mrrafil [7]3 years ago
5 0

Answer:

The maximum wavelength is 492 nm.

Explanation:

Given that,

Angular separation \theta=3.0\times10^{-5}\ rad

Suppose a telescope with a small circular aperture of diameter 2.0 cm.

We need to calculate the maximum wavelength

Using formula of angular separation

\sin\theta=\dfrac{1.22\lambda}{d}

\lambda=\dfrac{d\sin\theta}{1.22}

Put the value into the formula

\lambda=\dfrac{2.0\times\sin(3\times10^{-5})}{1.22}

For small angle \sin\theta\approx\theta

\lambda=\dfrac{0.02\times3\times10^{-5}}{1.22}

\lambda=4.92\times10^{-7}\ m

\lambda=492\ nm

Hence, The maximum wavelength is 492 nm.

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Chapter 14, Problem 042 A flotation device is in the shape of a right cylinder, with a height of 0.588 m and a face area of 4.19
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     Where \rho_w is the density of freshwater which has a constant value

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     Let the final height of the device under the water be  =  h_f

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This is mathematically represented as

          \rho_c g V_n = \rho_w gV_f

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So      \frac{0.346 \rho_w}{\rho_w} = \frac{h_f}{h}

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              = \frac{g A \rho}{2}  [h^2 - h_f^2]

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