In a nuclear power plant, energy is released from the nuclei of atoms. The correct option among all the options given in the question is the first option. Huge amount of thermal energy is released by the breaking of the uranium atoms. This energy is used for turning a turbine that produces electricity. It is a very clean method of producing electricity.
Answer:
5/6 = 0.833
Explanation:
From conservation of momentum,
m1*u1 + m2*u2 = (m1+m2)*v
v = (m1*u1 + m2*u2)/(m1*m2)
Putting in the values, we get, v = 5/6 = 0.833
Answer:
<h3>3.33m/s</h3>
Explanation:
Using the law of conservation of momentum
m1u1 + m2u2 = (m1+m2)v
m1 and m2 are the masses of the object
u1 and u2 are the velocities
v is the final velocity
Given
m1 = 50g
u1 = 10m/s
m2 = 100g
u2 = 0m/s (stationary ball)
Required
Common velocity v
Substitute
50(10) + 100(0) = (50+100)v
500 = 150v
v = 500/150
v = 3.33m/s
Hence the velocity of each ball immediately after the collision is 3.33m/s
Period of a simple pendulum = 2π √(L/G)
(360s/100) = 2π √(1.2m/G)
1.8s / π = √1.2m / √G
√G · (1.8s/π) = √1.2m
√G = (π · √1.2m) / 1.8s
Square each side:
G = π² · 1.2m / 3.24 s²
G = (1.2 · π² / 3.24) m/s²
G = 3.66 m/s²
So I just went and looked up Mars gravity. Floogle says it's 3.711 m/s² there.
That seems awfully close ... only 1.4% greater than our astronauts measured.
You don't suppose . . . . .
