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Nutka1998 [239]
3 years ago
13

Difference between basic units and derived unit​

Physics
1 answer:
Molodets [167]3 years ago
4 0

Answer:

<em><u>Basic</u></em><em><u> </u></em><em><u>units</u></em><em><u>=</u></em><em><u>those</u></em><em><u> </u></em><em><u>units</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>measurement</u></em><em><u> </u></em><em><u>which</u></em><em><u> </u></em><em><u>do not</u></em><em><u> </u></em><em><u>depend</u></em><em><u> </u></em><em><u>upon</u></em><em><u> </u></em><em><u>any</u></em><em><u> </u></em><em><u>other</u></em><em><u> </u></em><em><u>units</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>called</u></em><em><u> </u></em><em><u>basic</u></em><em><u> </u></em><em><u>units</u></em><em><u>.</u></em><em><u> </u></em><em><u>Example</u></em><em><u> </u></em><em><u>length</u></em><em><u>,</u></em><em><u> </u></em><em><u>mass</u></em><em><u>,</u></em><em><u> </u></em><em><u>time</u></em><em><u>,</u></em><em><u> </u></em><em><u>current</u></em><em><u> </u></em><em><u>etc</u></em><em><u>.</u></em><em><u> </u></em>

<em><u>Derived</u></em><em><u> </u></em><em><u>units</u></em><em><u>=</u></em><em><u>those</u></em><em><u> </u></em><em><u>units</u></em><em><u> </u></em><em><u>which</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>expressed</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>terms</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>fundamental</u></em><em><u> </u></em><em><u>units</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>called</u></em><em><u> </u></em><em><u>derived</u></em><em><u> </u></em><em><u>units</u></em><em><u>.</u></em><em><u> </u></em><em><u>Example</u></em><em><u> </u></em><em><u>area</u></em><em><u>,</u></em><em><u> </u></em><em><u>volume</u></em><em><u>,</u></em><em><u> </u></em><em><u>density</u></em><em><u> </u></em><em><u>etc</u></em><em><u>.</u></em><em><u> </u></em>

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A solid conducting sphere with radius R carries a positive total charge Q. The sphere is surrounded by an insulating shell with
Illusion [34]

Answer:

Explanation:

Volume of the insulating shell is,

V_{shell}=\frac{4}{3}\pi(R^3_2-R^3_1)

Charge density of the shell is,

\rho=\frac{Q_{shell}}{\frac{4}{3}\pi(R^3_2-R^3_1)}

Here, R_2 =2R, R_1 =R \,and\, Q_{shell} =-Q

\rho=\frac{Q_{shell}}{\frac{4}{3}\pi((2R)^3-R^3)}=\frac{-3Q}{28\piR^3}

B)

The electric field is E=\frac{1}{4\pi\epsilon_0}\frac{Qr}{R^3}

For 0 <r<R the electric field is zero, because the electric field inside the conductor is zero.

C)

For R <r <2R According to gauss law

E(4\pi r^2)=\frac{Q}{\epsilon_0}+\frac{4\pi\rho}{3\epsilon_0}(r^3-R^3)

substitute \rho=\frac{-3Q}{28\piR^3}

E=\frac{2}{7\pi\epsilon_0}\frac{Q}{r^2}-\frac{Qr}{28\piR^3}

D)

The net charge enclosed for each r in this range is positive and the electric field is outward

E)

For r>2R

Charge enclosed is zero, so electric field is zero

8 0
3 years ago
Substitute the value 26.7 (or the exact value of 80/3) for x in the first of the original equation (x + y = 40) to find the valu
Tatiana [17]

Complete Question

The complete question is shown on the first uploaded image

Answer:

the value of  y = 13.3

Explanation:

From the question we are told that

       The equation is  (x + y = 40)

        The first value of x is  x_1 =  26.7

        The second equation is  (0.75x + 1.5y = 40)

So  substituting x_1

     26.7 + y  =  40

=>   y = 13.3

Now substituting y and  x_1 into second equation

       0.75(26.7) +  (1.5* 13.3) =  40

 =>  40 = 40

So  y = 13.3

         

4 0
3 years ago
What is the weight on mass
Gre4nikov [31]

Answer:

6.39×10^23 kg is the weight on mass

3 0
1 year ago
A grating has 320 lines/mm. How many orders of the visible wavelength 551 nm can it produce in addition to the m = 0 order
Anastaziya [24]

Answer:

6

Explanation:

Given that

dsinθ = mλ,

now, if sinθ = 1, then

m = d / λ, where

m = order of interference

d = distance between the slits

λ = wavelength of light

this is the formula we would use to solve the question

d = 1 / 320 lines/mm

d = 1 / 320*10^3

d = 3.125*10^-6 m

At λ = 551 nm, we have

m = 3.125*10^-6 / 551*10^-9

m = 5.67

5.67 ~ 6

thus, we can say that the orders of visible wavelength 551 nm, can produce is 6

4 0
3 years ago
If the real gi tract is 9 meters long, the model you created is what fraction of the real one
Sedbober [7]

Answer:

a

Explanation:

a

7 0
3 years ago
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