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Nutka1998 [239]
3 years ago
13

Difference between basic units and derived unit​

Physics
1 answer:
Molodets [167]3 years ago
4 0

Answer:

<em><u>Basic</u></em><em><u> </u></em><em><u>units</u></em><em><u>=</u></em><em><u>those</u></em><em><u> </u></em><em><u>units</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>measurement</u></em><em><u> </u></em><em><u>which</u></em><em><u> </u></em><em><u>do not</u></em><em><u> </u></em><em><u>depend</u></em><em><u> </u></em><em><u>upon</u></em><em><u> </u></em><em><u>any</u></em><em><u> </u></em><em><u>other</u></em><em><u> </u></em><em><u>units</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>called</u></em><em><u> </u></em><em><u>basic</u></em><em><u> </u></em><em><u>units</u></em><em><u>.</u></em><em><u> </u></em><em><u>Example</u></em><em><u> </u></em><em><u>length</u></em><em><u>,</u></em><em><u> </u></em><em><u>mass</u></em><em><u>,</u></em><em><u> </u></em><em><u>time</u></em><em><u>,</u></em><em><u> </u></em><em><u>current</u></em><em><u> </u></em><em><u>etc</u></em><em><u>.</u></em><em><u> </u></em>

<em><u>Derived</u></em><em><u> </u></em><em><u>units</u></em><em><u>=</u></em><em><u>those</u></em><em><u> </u></em><em><u>units</u></em><em><u> </u></em><em><u>which</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>expressed</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>terms</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>fundamental</u></em><em><u> </u></em><em><u>units</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>called</u></em><em><u> </u></em><em><u>derived</u></em><em><u> </u></em><em><u>units</u></em><em><u>.</u></em><em><u> </u></em><em><u>Example</u></em><em><u> </u></em><em><u>area</u></em><em><u>,</u></em><em><u> </u></em><em><u>volume</u></em><em><u>,</u></em><em><u> </u></em><em><u>density</u></em><em><u> </u></em><em><u>etc</u></em><em><u>.</u></em><em><u> </u></em>

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A ball of mass M is suspended by a thin string (of negligible mass) from the ceiling of an elevator.uploaded image
lilavasa [31]

Answer:

(a) The elevator is traveling upward and its upward velocity is decreasing as it nears a stop at a higher floor.  T > mg

(b) The elevator is traveling upward and its upward velocity is increasing as it begins its journey towards a higher floor. T > mg

(c) The elevator is traveling downward and its downward velocity is decreasing as it nears a stop at a lower floor. T < mg

(d) The elevator is traveling downward at a constant velocity. T = mg

(e) The elevator is traveling downward and its downward velocity is increasing. T < mg

(f) The elevator is stationary and remains at rest. T = mg

Explanation:

To answer this question, consider all the forces acting on the elevator.

The mass of the ball acting downwards due to gravity = mg

The tension on the string depends on upward or downwards force on the ball. T = m(a+g)

where a is acceleration and increase in velocity causes increase in acceleration, and vice versa. (a = v/t)

(a) The elevator is traveling upward and its upward velocity is decreasing as it nears a stop at a higher floor.

If the upward velocity is decreasing, its acceleration is also decreasing, and acceleration is not equal to Zero

T = m(a+g) > mg

(b) The elevator is traveling upward and its upward velocity is increasing as it begins its journey towards a higher floor.

If the upward velocity is increasing, its acceleration is also increasing.

Then, T = m(a+g) > mg

(c) The elevator is traveling downward and its downward velocity is decreasing as it nears a stop at a lower floor.

If the downward velocity is decreasing, its acceleration is also decreasing, and acceleration is not equal to Zero

T = m(a-g) < mg

(d) The elevator is traveling downward at a constant velocity

At constant velocity, acceleration is zero, because acceleration is the rate of change of velocity.

T = m(0+g) = mg

(e) The elevator is traveling downward and its downward velocity is increasing

If the downward velocity is increasing, its acceleration is also increasing

T = m(a-g) < mg

(f) The elevator is stationary and remains at rest.

if the elevator is at rest, its acceleration is zero

T = m(0+g) = mg

6 0
3 years ago
A skateboarder with a mass of 60 kg moves with a force of 20 N. What is her acceleration?
Zanzabum

Explanation:

Solution,

  • Mass(m)= 60 kg
  • Force (F)= 20 N
  • Acceleration (a)= ?

We know that,

  • F=ma
  • a=F/m
  • a=20/60
  • a=0.333 m/s²

So, her acceleration is 0.333 m/s².

4 0
2 years ago
There is a bell at the top of a tower that is 45 m high. The bell weighs 190 N. The bell has ____________
salantis [7]

Answer:

The bell has a potential energy of 8550 [J]

Explanation:

Since the belt is 45 [m] above ground level, only potential energy is available. And this energy can be calculated by means of the following equation.

E_{p}= W*h\\E_{p} = 190*45\\E_{p}=8550[J]

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3 years ago
24. Most cleaning solutions like soap, with a pH of 8-9 are examples of a(n)
Sphinxa [80]

24. A, natural ph scale for it not to be acidic is 7-8

25. A, not sure about this one

26. A, looked it up

27. A, because it has to be shaken up to make the mixture appear and taste more combined.

28. D, i just guessed

29. D, that answer is stupid so it is the answer because it said not a property

30. A, looked it up

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You stand on top a building 44 m tall with a water balloon. You drop the water balloon from rest. How fast is the balloon moving
Alecsey [184]
<h2>The balloon is moving when it is halfway down the building at 20.78 m/s.</h2>

Explanation:

We have equation of motion v² = u² + 2as

Initial velocity, u = 0 m/s  

Acceleration, a = 9.81 m/s²  

Displacement, s = 0.5 x 44 = 22 m

Substituting  

v² = u² + 2as

v² = 0² + 2 x 9.81 x 22

v² = 431.64

v = 20.78 m/s

Velocity at 22 m = 20.78 m/s

The balloon is moving when it is halfway down the building at 20.78 m/s.

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3 years ago
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