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Novosadov [1.4K]
3 years ago
11

How are compressions and rarefactions produced by the tuning fork?

Chemistry
1 answer:
AnnZ [28]3 years ago
8 0
When the prong of a tuning fork next to the tube moves toward the tube, a compression enters the tube. When the prong swings away, in the opposite direction, a rarefaction follows the compression. As the source vibrates, a series of compressions and rarefactions is produced.
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450.0 mL of an unknown gas has its pressure decreased from 0.07 atm to 0.04 atm. Assuming temperature remains constant, what wou
tino4ka555 [31]

The final volume of the unknown gas is 787.5 ml

Given:

volume of unknown gas = 450.0 mL

initial pressure of unknown gas = 0.07 atm

final pressure of unknown gas = 0.04 atm

To Find:

final volume of the unknown gas

Solution:

Substituting these values into Boyle’s law, we get

P1V1 = P2V2

(0.07)(450) = (0.04)V2

V2 = (0.07)(450)/(0.04)

V2 = 787.5

So, final volume of the unknown gas is 787.5 ml

Learn more about Volume here:

brainly.com/question/25736513

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4 0
2 years ago
What would be the final temperature of a 73.174g sample
madreJ [45]

The final temperature is -138 °C.

Explanation:

Using the equation of specific heat

Q = m*c* del T

We can easily find the final temperature of a 73.174 g of copper sample. As we know that specific heat is the amount of energy required to raise the temperature of the object to 1°C.

The specific heat of copper is known as 0.387 J/g°C and the initial temperature is said as 102 °C . The mass is given as 73.174 g. The heat released is 6800 J.

Since the heat is released the Q value will be negative.

-6800=0.387*73.174*(T_{final}-102)

T_{final}-102=\frac{-6800}{0.387*73.174} =-240

T_{final} = -240+102=-138

Thus, the final temperature is -138 °C.

3 0
4 years ago
A fixed amount of gas at 25.0°C occupies a volume of 10.0 L when the pressure is 667 torr. Use Boyle's law to calculate the pres
zaharov [31]

Answer:

The pressure, when the volume is reduced to 7.88L, is 846 torr (option A)

Explanation:

Step 1: Data given

The temperature of a gas = 25.0°C

AT 25 °C the gas occupies a volume of 10.0L and a pressure of 667 torr.

The volume reduces to 7.88 L but the temperature stays constant.

Step 2: Boyle's law

(P1*V1)/T1 = (P2*V2)/T2

 ⇒ Since the temperature stays constant, we can simplify to:

P1*V1 = P2*V2

⇒ with P1 = the initial pressure 667 torr

⇒ with V1 = the initial volume = 10.0 L

⇒ with P2 = the final pressure = TO BE DETERMINED

⇒ with V2 = the final volume = 7.88L

P2 = (P1*V1)/V2

P2 = (667*10.0)/7.88

P2 = 846 torr

The pressure, when the volume is reduced to 7.88L, is 846 torr (option A)

6 0
3 years ago
What's the atomic weight of salt ?
marta [7]

Answer:

58.44 g/mol

Explanation:

58.44 g/mol

4 0
3 years ago
Read 2 more answers
water (H2O) and carbon dioxide (CO2) are similar because they both contain at least one oxygen A.) atom. B.) mixture C.) molecul
vova2212 [387]

Answer:

a

Explanation:

it is A because h20 and c02 are molecules while what make them up are atoms

5 0
4 years ago
Read 2 more answers
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