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cluponka [151]
3 years ago
10

35 points and brainiest is it A, B, C, D

Engineering
2 answers:
scoray [572]3 years ago
7 0
I believe the correct answer is C.
wel3 years ago
5 0

Answer:

c thereeeeeeeeeeeeeeeeee

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What year is gas powered cars expected stop being produced
Ksivusya [100]

Answer:

2035

Explanation:

The governors of a dozen U.S. states including California, New York, Massachusetts and North Carolina called on President Joe Biden on Wednesday to back ending sales of new gasoline-powered vehicles by 2035, a dramatic shift away from fossil fuels.

8 0
3 years ago
Read 2 more answers
dentify a semiconducting material and provide the value of its band gap) that could be used in: (a) (1 point) red LED (b) (1 poi
OLga [1]

Answer:

(a) Aluminum Indium Gallium Phosphide (AlInGaP). Band gap = 1.81eV  ≈ 2eV

(b) Gallium Nitride (GaN). Band Gap = 3.4eV

(c) Aluminium Gallium Arsenide (AlGaA). Band Gap = 1.42eV ≈ 2.16eV

(d) Zinc Selenide (ZnSe). Band Gap = 2.82eV

(e) Gallium Phosphide (GaP). Band Gap = 2.24eV

Explanation:

LED's are semi-conducting materials that convert electrical energy to light energy. The light color emitted from the LED depends on the semi-conducting material and other compositions.

The band gap of the semi-conductor determines its wavelength. High band gap semi-conductors emit lower wavelengths which means greater power(UV semi-conducting macterials fall under this category).

5 0
3 years ago
A 200-L tank (see Fig. P4.107) initially contains water at 100 kPa and a quality of 1%. Heat is transferred to the water, thereb
Tomtit [17]

Answer:

25.46 MJ

Explanation:

continuity : m3 - m1 = -m<em>e</em>

<em>Energy Equation: m3u3 - m1u1 = -meue + 1Q3</em>

<em />

<em>See the image attached (Well typed out format)</em>

5 0
4 years ago
Large quantities of liquefied natural gas (LNG) are shipped by ocean tanker. At the unloading port, provision is made for vapori
kodGreya [7K]

Answer:

yfyuhvckydfxcvkjyfvgrjfvhkhgfyhtfhchghjgyfvyghvhygvkuh

Explanation:

6 0
4 years ago
The water in a large lake is to be used to generate electricity by the installation of a hydraulic turbine-generator at a locati
Lynna [10]

Answer:

a) 0.76

b) 0.80

c) 1964 kW

Explanation:

GIVEN DATA:

\dot m = 5000 kg/s

Assume Mechanical energy at exist is negligible

A) Take lake bottom as reference, and then kinetic and potential energy  are taken as zero.

change in mechanical energy is givrn as

e_{in} - e_{out} = \frac{P}{\rho} - 0 = gh = 9.81 \times 50( \frac{1 kJ/kg}{1000 m^2/s^2}

                         = 0.491 kJ/kg

\Delta \dot E_{mec} = \dot m (e_{in} - e_{out}) = 5000 \times 0.491 = 2455 kW

\eta_{OVERALL}  = \frac{\dot W}{\Delta \dot E_{mec}} = \frac{1862}{2455} = 0.76

B) \eta -{gen} = \frac{\eta_{overall}}{\eta_{gen}} = \frac{0.76}{0.95} = 0.80

c) \dot W_{shaft} = \eta_{overall} \left | \Delta \dot E_{mec} \right | = 0.80(2455)

\dot W_{shaft} = 1964 kW

7 0
4 years ago
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