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2 years ago

Round 0.731 to the nearest hundredth.

Mathematics

2 answers:

Sedaia [141]2 years ago

8 0

Answer: 0.73

Step-by-step explanation:

kolbaska11 [484]2 years ago

3 0

Answer:0.73

Step-by-step explanation: none the answer is right

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a test for a certain drug has a 0.1% probability of producing a false positive. if a company hired 500 drug-free employees, what

Natasha_Volkova [10]

The probability of obtaining at least 1 false positive if the number of employees is 500 is 0.5

Probability

In the statistics concept, the probability refers the possible number of way of happening the particular event.

Given,

A test for a certain drug has a 0.1% probability of producing a false positive.

Here we need to find the probability of obtaining at least 1 false positive if a company hired 500 drug-free employees.

In the given question, we have the following values,

=> number of employees = 500

=> Probability of false positive = 0.1%

So, the probability of obtaining at least 1 false positive is calculated as,

=> 500 x 0.1/100

=> 5 x 0.1

=> 0.5

Therefore, the probability of obtaining at least 1 false positive is 0.5.

To know more about Probability here.

brainly.com/question/11234923

#SPJ4

6 0

1 year ago

At andres birthday party 3 pizzas were ordered for lunch. Each pizza was divided into 8 equal slices. Each child ate 2 pieces an

pogonyaev

Answer: I dont know if im right for sure but the answer should be 4

Step-by-step explanation

8 goes into 2 4 times (8 divided by 2 = 4)

Each child ate 2 pieces (4-2=2)

so therefore for it to be 2 pieces left over there were 4 kids I think.

4 0

2 years ago

Read 2 more answers

Please please help me. i’ll literally send you money. i need to pass please help

mihalych1998 [28]

<h3>Answer: Approximately 6.4 units</h3>

==================================================

Explanation:

The origin is the point (0,0)

Use the distance formula to find the distance from (0, 0) to (4, -5)

Let

$(x_1,y_1) = (0,0)\\\\(x_2,y_2) = (4,-5)\\\\$

be our two points. Plug those values into the distance formula below and use a calculator to compute

$d = \sqrt{\left(x_1-x_2\right)^2+\left(y_1-y_2\right)^2}\\\\d = \sqrt{\left(0-4\right)^2+\left(0-(-5)\right)^2}\\\\d = \sqrt{\left(0-4\right)^2+\left(0+5\right)^2}\\\\d = \sqrt{\left(-4\right)^2+\left(5\right)^2}\\\\d = \sqrt{16+25}\\\\d = \sqrt{41} \ \text{ exact distance}\\\\d \approx 6.40312 \ \text{ approximate distance}\\\\d \approx 6.4\\\\$