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3 years ago

When aqueous solutions of Li3PO4 and MgSO4 are mixed, Mg3(PO4)2 is a precipitate

Chemistry

1 answer:

Lesechka [4]3 years ago

8 0

Answer:

Li2SO4

Explanation:

Balance the reaction of Li3PO4 + MgSO4 = Li2SO4 + Mg3(PO4)2 using this chemical equation balancer!

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Why is thre no gas bubble whene there is citric acid?answer all the questions in detail.

kaheart [24]

Answer:

This is because the carbon dioxide gas that dissolved in the water is not very soluble. ... After the citric acid solution and baking soda react, carbon dioxide gas is formed, along with other products.

8 0

2 years ago

The following reactions have the indicated equilibrium constants at a particular temperature: N2(g) + O2(g) ⇌ 2NO(g) Kc = 4.3 ×

Anuta_ua [19.1K]

Answer:

$Kc=~1.49x10^3^4}$

Explanation:

We have the reactions:

A: $N_2_(_g_) + O_2_(_g_) 2NO_(_g_)~~~~~~Kc = 4.3x10^-^2^5$

B: $2NO_(_g_)+~O_2_(_g_)~2NO_2_(_g_)~~~Kc = 6.4x10^9$

Our target reaction is:

$4NO_(_g_) N_2_(_g_) + 2NO_2_(_g_)$

We have $NO_(_g_)$ as a reactive in the target reaction and $NO_(_g_)$ is present in A reaction but in the products side. So we have to flip reaction A.

A: $2NO_(_g_) N_2_(_g_) + O_2_(_g_) ~Kc =\frac{1}{4.3x10^-^2^5}$

Then if we add reactions A and B we can obtain the target reaction, so:

A: $2NO_(_g_) N_2_(_g_) + O_2_(_g_) ~Kc =\frac{1}{4.3x10^-^2^5}$

B: $2NO_(_g_)+~O_2_(_g_)~2NO_2_(_g_)~Kc=6.4x10^9$

For the final Kc value, we have to keep in mind that when we have to add chemical reactions the total Kc value would be the multiplication of the Kc values in the previous reactions.

$4NO_(_g_) N_2_(_g_) + 2NO_2_(_g_)~~~Kc=\frac{6.4x10^9}{4.3x10^-^2^5}$

$Kc=~1.49x10^+^3^4}$

3 0

2 years ago

Pls help 20020200202

Ronch [10]

tell me what to do dudette

6 0

2 years ago

iron has a density of 7.86 g cm3 could a block of metal with a mass of 18.2 and a volume of 2.56 cm^3 be iron?

satela [25.4K]

The density of the block will be "7.11 gm/cm³". A further explanation is provided below.

Given values are:

Density of iron,

$7.86 \ g/cm^3$

Mass of block of metal,

$18.2 \ gm$

Volume of block,

$2.56 \ cm^3$

By using the formula,

→ $Density = \frac{Mass}{Volume}$

then,

→ The density of block will be:

= $\frac{Mass}{Volume}$

= $\frac{18.2}{2.56}$

= $7.11 \ gm/cm^3$

Learn more:

brainly.com/question/10804879

7 0

2 years ago

Helium is an odorless, colorless gas at room temperature. It is less dense than air. That's why helium balloons float. It is a n

Zolol [24]

Answer:

Non-flammable
It is the only element that doesn't solidify under ordinary pressure and remains a liquid enven at absolute zero.
When it electricity runs through helium it glows a pale peach color.

5 0

3 years ago