Please help I’m strugglinggg Oml and this is due right now

a coin purse contains 3 quarters, 2 dimes, 1 nickle, and 4 pennies. what is the probability of selecting a nickle, then a dime w

mixer [17]

Answer:

.0222

The probability of selecting a nickle then a dime without replacement is 2.22%.

(1/10)*(2/9)= .0222

5 0

2 years ago

Holly drinks 2 litres of water each day.

natulia [17]

Answer:

14 litre

Step-by-step explanation:

1 week = 7 days

in 1 day holly drinks 2 L water

here, 7*2=14

4 0

2 years ago

Read 2 more answers

A random sample of 16 students selected from the student body of a large university had an average age of 25 years and a populat

eimsori [14]

Answer:

$t=\frac{25-24}{\frac{2}{\sqrt{16}}}=2$

$p_v =P(t_{15}>2)=0.0320$

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the true mean is significant higher than 24 years.

Step-by-step explanation:

1) Data given and notation

$\bar X=25$ represent the sample mean

$s=2$ represent the standard deviation for the sample

$n=16$ sample size

$\mu_o =24$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

Confidence =0.95 or 95%

$\alpha=0.05$

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the mean is higher than 24, the system of hypothesis would be:

Null hypothesis: $\mu \leq 24$

Alternative hypothesis: $\mu > 24$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{25-24}{\frac{2}{\sqrt{16}}}=2$

Calculate the P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=16-1=15$

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>2)=0.0320$

Conclusion

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the true mean is significant higher than 24 years.

3 0

2 years ago

find the least common denominator of the following rational expression 1/x-5 , x+3/x^2-10x+25, 7x/x^2-25

I am Lyosha [343]

Hello there!
Find the last common denominator of the following rational expression 1/x-5 , x+3/x^2-10x+25, 7x/x^2-25

Find the LCD.
$x^{2} (x-5)(x+5)$

Answer: $x^{2} (x-5)(x+5)$

5 0

2 years ago

Solo quero decirle a todos que Cristo les ama! El viene pronto y si tu no le aceptas en tu corazon te quedaras! El tiempo ya se

Ann [662]

Dios ha sido aceptado en mi corazon

8 0

3 years ago