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sergiy2304 [10]
3 years ago
12

Why do astronomers hypothesize that a massive black hole lies at the center of m87?

Physics
1 answer:
lana66690 [7]3 years ago
4 0
<h2>Answer:</h2>

According to <u>Einstein's theory of relativity</u>, a black hole is a <u>"singularity"</u> that consists of a region of the space in which the density of matter tends to infinity. In consequence, this huge massive body has a gravitational pull so strong that not even light can escape from it.

In addition, "the surface" of a black hole is called the event horizon, which is the border of space-time in which the events on one side of it can not affect an observer on the other side.  

In other words, at this border also called "point of no return", nothing can escape (not even light) and no event that occurs within it can be seen from outside.  

In this sense, and according to the relativity, it is possible to determine where a black hole is if it is "observed" an <em><u>enormous amount of energy released</u></em>. So, in accordance to this, galaxies like ours must have a black hole in its center.

On the other hand, the elliptical galaxy Mesier 87 (also called Virgo A, but from now on M87) was showing the above described behaviour, with enormous jets of high-energy particles shooting away from its vicinity . This was imaged by the Hubble Space Telescope years ago; that is why astronemers were hypothesizing about the existence of a massive black hole there.

Well now, on April, 10th 2019 this was demonstrated with the publication of the image, for the first time, of the event horizon of the black hole in M87. This is the first time in human history a picture of a black hole is taken.

This was done by the huge effort of diverse scientist and by the syncronization of eight radio telescopes scattered across the Earth (located at: Hawaii, Spain, Chile, Mexico, Arizona and the South Pole), which took the same point of the sky at the same time.

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A 2000 N net force will give a car with some amount of mass an acceleration of 4 m/s2
hammer [34]

Answer:

2m/s²

Explanation:

Given parameters:

Net force on the car  = 2000N

Acceleration = 4m/s²

Unknown:

Acceleration of a car twice the mass  = ?

Solution:

Let us first find the mass of the car;

 Force  = mass x acceleration

         Mass = \frac{Force }{acceleration}  

 Mass = \frac{2000}{4}   = 500kg

 Now,

     whose mass is twice that of the car

    Mass of the new car = 2 x 500  = 1000kg

So;

  Acceleration  = \frac{Net force }{mass}  

  Acceleration  = \frac{2000}{1000}  = 2m/s²

3 0
2 years ago
A light ray traveling through a material with an index of refraction of 1.2 is incident on a material that has an index of refra
zzz [600]

Answer:

compared to the incident angle, the refracted angle is 45.56⁰

Explanation:

From Snell's law;

n₁sin(I) = n₂sin(r)

Where;

n₁ is the refractive index of light in medium 1 = 1.2

n₂ is the refractive index of light in medium 2 = 1.4

I is the incident angle

r is the refractive angle

n = \frac{1}{sin(I)}\\\\sin(I) = \frac{1}{n}\\\\sin(I) =\frac{1}{1.2}\\\\sin(I) =0.8333\\\\I = sin^-{(0.8333)

I = 56.439⁰

Applying snell's law

n_1sin(I) = n_2sin(r)\\\\sin(r) = \frac{n_1sin(I) }{n_2}\\\\sin(r) = \frac{1.2*sin(56.439) }{1.4}\\\\sin(r) = 0.714\\\\r = sin^-(0.714)\\\\r = 45.56^o

Therefore, compared to the incident angle, the refracted angle is 45.56⁰

3 0
3 years ago
Two conducting spheres of different sizes are at the same potential. The radius of the larger sphere is four times larger than t
Sergeeva-Olga [200]

Answer:

0.8

Explanation:

The two spheres have the same potential, V.

Let the radius of the larger sphere be R and the radius of the smaller sphere be r,

=> R = 4r

Let the charge on the smaller sphere be q. Hence, the larger sphere will have charge Q - q.

The potential of the smaller sphere will be:

V_S = \frac{kq}{r}

The potential of the larger sphere will be:

V_L = \frac{k(Q - q)}{R}

Inputting R = 4r,

V_L = \frac{k(Q - q)}{4r}

Since V_S = V_L = V,

\frac{k(Q - q)}{4r} = \frac{kq}{r}

=> Q - q = 4q

=> 5q = Q

q = 0.2Q

The fraction of the charge Q that rests on the smaller sphere is 0.2

The charge of the larger sphere is:

Q - q = Q - 0.2Q = 0.8Q

∴ The fraction of the total charge Q that rests on the larger sphere is 0.8

7 0
3 years ago
Can someone explain how they got their answer or how I get the change in number? :(
enyata [817]

Answer:

See Below

Explanation:

Okay, I thinkkk what it is asking by what you summarzied for me issss:

They split the total time into four quarters. They then took (for the first quarter) the start time. Then when the first quarter ends and the second quarter starts is the "end" time.

They then subtract the start time of the second quarter from the end time of the first quarter.

I hope this helps, good luck! :D

5 0
2 years ago
Which condition is a neuron in when the outside of the neuron has a net positive charge and the inside has a net negative charge
White raven [17]
The condition is a neuron in when the outside of the neuron has a net positive charge and the inside has a net negative charge (due to accumulation of more sodium ions) is C. resting potential. T<span>he </span>resting membrane<span> </span>potential<span> of a </span>neuron<span> is approximately -70 mV (mV=</span><span>millivolt)</span>
8 0
3 years ago
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