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3 years ago

An object with a velocity of

Physics

1 answer:

algol [13]3 years ago

4 0

Answer:

v = 1.7 m/s

Explanation:

Given that,

Initial velocity of the object, u = 1 m/s

Acceleration of the object, a = 1 m/s²

We need to find the velocity of the object after moving 1 m. Let v be the velocity. Using third equation of kinematics to find it i.e.

$v^2-u^2=2ad\\\\v^2=2ad+u^2\\\\v^2=2(1)(1)+1^2\\\\v=\sqrt3\\\\v=1.7\ m/s$

So, the final velocity of the object is 1.7 m/s.

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Answer:

a. Picture attached

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d. It makes sense cosidering that a normal heart beat rate is between 60 and 100 beats per minute (bpm).

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$a: acceleration\\t: time$

Considering the characteristics of the problem and that distance and velocity are specified, the acceleration is constant, for that reason we use the equations of uniformly accelerated motion as follows:

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If we reorganize the equations, considering that $x_{0}$ and $v_{0}$ are zero because motion starts from rest , we have:

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Finally, the analysis of the result leaves us to understand why the normal heart beat rate varies between 60 and 100 bpm.

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